英文:
How do I print numbers in range using a method that takes a list as a parameter in JAVA?
问题
这是Mooc Java第3周的第15个练习。以下是练习的要求:
"在练习模板中创建方法public static void printNumbersInRange(ArrayList<Integer> numbers, int lowerLimit, int upperLimit)
。该方法打印给定列表中数值在范围[lowerLimit, upperLimit]内的数字。"
我的代码似乎没问题,当我尝试不同的值时,它给出了正确的结果。然而,当我运行测试时,我收到了以下错误消息:
"类PrintInRange的方法printNumbersInRange(ArrayList, int, int)丢失。"
你能帮我解决问题吗?我已经卡在这里一段时间了。以下是我的代码,我只是在主方法中调用了这个方法来进行测试。谢谢!
import java.util.ArrayList;
public class PrintInRange {
public static void main(String[] args) {
// 在这里尝试你的方法
ArrayList<Integer> list = new ArrayList<>();
list.add(1);
list.add(2);
list.add(3);
list.add(6);
list.add(360);
list.add(-1);
list.add(10000);
System.out.println("在范围[300, 100000]内的数字:");
numbersInRange(list, 300, 100000);
}
public static void numbersInRange(ArrayList<Integer> numbers, int lowerLimit, int upperLimit) {
for (Integer value : numbers) {
if (value >= lowerLimit && value <= upperLimit) {
System.out.println(value);
}
}
}
}
英文:
This is week 3 - exercise 15 of Mooc Java. This is what the exercise is looking for
>"Create the method public static void printNumbersInRange(ArrayList<Integer> numbers, int lowerLimit, int upperLimit)
in the exercise template. The method prints the numbers in the given list whose values are in the range [lowerLimit, upperLimit]."
My code seems to be fine and it gives me the right results when I try different values. However, when I run the tests I get this error
>"Method printNumbersInRange(ArrayList, int, int) of class PrintInRange missing."
Could you guys give me some light? I have been stuck for a bit here. Follow the code below, I called the method in the main just to test.
Thanks!
import java.util.ArrayList;
public class PrintInRange {
public static void main(String[] args) {
// Try your method here
ArrayList<Integer> list = new ArrayList<>();
list.add(1);
list.add(2);
list.add(3);
list.add(6);
list.add(360);
list.add(-1);
list.add(10000);
System.out.println("The numbers in the range[300, 100000]");
numbersInRange(list, 300, 100000);
}
public static void numbersInRange(ArrayList<Integer>numbers, int lowerLimit, int upperLimit){
for (Integer value : numbers){
if(value >= lowerLimit && value <= upperLimit){
System.out.println(value);
}
}
}
}
答案1
得分: 1
以下是代码部分的翻译:
包 com.example;
import java.util.ArrayList;
import java.util.List;
/**
* 创建于 2020 年 8 月 9 日。
*
* 作者:Sergio
* 自 2020 年 8 月 9 日起
*/
public class PrintRange {
public static void main(String[] args) {
List<Integer> list = new ArrayList<>();
list.add(1);
list.add(2);
list.add(3);
list.add(6);
list.add(360);
list.add(-1);
list.add(10000);
System.out.println("范围内的数字[300, 100000]");
numbersInRange(list, 300, 100000);
}
static void numbersInRange(List<Integer> numbers, int lowerLimit, int upperLimit) {
numbers.stream()
.filter(itemNumber -> itemNumber >= lowerLimit && itemNumber <= upperLimit)
.forEach(System.out::println);
}
}
输出部分没有需要翻译的内容。
英文:
The solution is
package com.example;
import java.util.ArrayList;
import java.util.List;
/**
* Created on 8/9/20.
*
* @author sergio
* @since 8/9/20
*/
public class PrintRange {
public static void main(String[] args) {
List<Integer> list = new ArrayList<>();
list.add(1);
list.add(2);
list.add(3);
list.add(6);
list.add(360);
list.add(-1);
list.add(10000);
System.out.println("The numbers in the range[300, 100000]");
numbersInRange(list, 300, 100000);
}
static void numbersInRange(List<Integer> numbers, int lowerLimit, int upperLimit) {
numbers.stream()
.filter(itemNumber -> itemNumber >= lowerLimit && itemNumber <= upperLimit)
.forEach(System.out::println);
}
}
Output:
The numbers in the range[300, 100000]
360
10000
Process finished with exit code 0
答案2
得分: 1
以下是您要翻译的内容:
package com.company;
import java.util.ArrayList;
public class PrintInRange {
public static void main(String[] args) {
// 在这里尝试您的方法
ArrayList<Integer> list = new ArrayList<>();
list.add(1);
list.add(2);
list.add(3);
list.add(6);
list.add(360);
list.add(-1);
list.add(10000);
System.out.println("在范围[300, 100000]内的数字");
printNumbersInRange(list, 300, 100000);
}
public static void printNumbersInRange(ArrayList<Integer> numbers, int lowerLimit, int upperLimit){
for (Integer value : numbers){
if(value >= lowerLimit && value <= upperLimit){
System.out.println(value);
}
}
}
}
英文:
You can try this one
package com.company;
import java.util.ArrayList;
public class PrintInRange {
public static void main(String[] args) {
// Try your method here
ArrayList<Integer> list = new ArrayList<>();
list.add(1);
list.add(2);
list.add(3);
list.add(6);
list.add(360);
list.add(-1);
list.add(10000);
System.out.println("The numbers in the range[300, 100000]");
printNumbersInRange(list, 300, 100000);
}
public static void printNumbersInRange(ArrayList<Integer>numbers, int lowerLimit, int upperLimit){
for (Integer value : numbers){
if(value >= lowerLimit && value <= upperLimit){
System.out.println(value);
}
}
}
}
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