Validating inputs in a function in java to avoid duplicate data other than non entry with default of 0 (No database )

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英文:

Validating inputs in a function in java to avoid duplicate data other than non entry with default of 0 (No database )

问题

我有三个整数变量,每个都有默认值为0。我想将每个值更新为与其他值不同的值。如果我尝试将两个变量更新为相同的值,验证应该允许。我卡在程序的验证部分上。请问有人可以指导我吗?

public static int ValidateChoice(int choice, int firstChoice, int secondChoice, int thirdChoice, int totalCredit) {

    // TO DO - Add Code to:
    // 验证用户菜单选择(int choice 方法参数)
    /* 根据以下给定的注册业务规则验证:
       不允许注册程序未显示的其他课程
       不允许多次注册相同的课程
       不允许注册超过9学分(例如,不超过3门课程)
      */    

    // 事实上,选择只限于七个选项
    // 超出七个或小于1都被视为无效
    if (choice > 8 || choice < 0) {
        return -1;
    }

    // 从这里开始是我的问题

    /// 选择的两门课程不应相同 
    // 因此,通过if中的条件捕获不当提交的课程
    // 初始状态 thirdChoice=0 secondChoice=0 firstChoice=0
    else if (firstChoice == secondChoice || firstChoice == thirdChoice || secondChoice == thirdChoice) {
        return -2;
    }

   // 到此为止

    // 课程的总学分最多为9学时
    else if (totalCredit > 9) {
        return -3;
    } else {
       return 0;  
    }
}
英文:

I have three integer variable of which each has default value of 0. I want to update the values each to a value that is unique from the other. In case I try update two variable to same value I should be allowed by the validation. I am stuck on writing the validation part of the program. Please can anyone guide me?

 public static int ValidateChoice(int choice, int firstChoice, int secondChoice, int thirdChoice, int totalCredit) {

    // TO DO - Add Code to:
    // Validate user menu selection (the int choice method argument)
    /* against the given registration business rules below:
       No registration of other courses not displayed by the program
       No registration more than once for the same course
       No registration for more than 9 credit hours (e.g. no more than 3 
       courses)
      */    

    //by fact the choice are limited to seven option 
    //anything beyond seven or below 1 is considered invalid
    if(choice &gt; 8 || choice &lt; 0){
        return -1;
        
    }

    //my problem is from here

    ///No two courses chosen should be the same 
    //therefore blacklisting the inappropriate submission of course is  captured by the condition in the if
    // initial state thirdChoice=0 secondChoice=0 firstChoice=0
    else if((firstChoice==secondChoice || firstChoice== thirdChoice || secondChoice==thirdChoice)){
        
        return -2;
    }

   // upto here

    //the total credit for the course is upto 9 hours
    else if(totalCredit &gt; 9) {
        return -3;
    }
    else {
       return 0;  
    }
}

答案1

得分: 0

不太清楚如何处理默认值,我尝试提供两个选项。我假设return 0是验证通过的返回值。

如果要求仅是在两个值相等时拒绝验证,那么只需具有以下条件即可:

if (firstChoice == secondChoice || 
    firstChoice == thirdChoice || secondChoice == thirdChoice) {
    return -2;
}
return 0;

与默认值无关。

如果要验证所有值为0的字段,检查非0字段是否相等,条件可以如下所示:

if ((firstChoice != 0 && firstChoice == secondChoice) || 
    (firstChoice != 0 && firstChoice == thirdChoice) || (secondChoice != 0 && secondChoice == thirdChoice)) {
    return -2;
}
return 0;

这种方式可以验证值为0的字段。

英文:

As not very clear what to do with defaults, i try to post 2 options. I assume return 0 as the validation passed return value.

If the requirement is simply to reject validation if 2 values are equal, it should be enough to have the condition

 if(  firstChoice==secondChoice || 
              firstChoice== thirdChoice || secondChoice==thirdChoice){
              
              return -2;
 }
 return 0;

indipendently from defaults.

If instead you should validate anyway all fields with value 0 and check for equality the non-0 fields, the condition can became as follows

 if(  (firstChoice!=0 &amp;&amp; firstChoice==secondChoice) || 
              (firstChoice!=0 &amp;&amp; firstChoice== thirdChoice) || (secondChoice !=0 &amp;&amp; secondChoice==thirdChoice)){
              
              return -2;
 }
 return 0;

in this way fields with value 0 are validated

答案2

得分: 0

使用这个:

boolean isInvalid = firstChoice != 0 ?
(firstChoice == secondChoice || firstChoice == thirdChoice) :
(secondChoice != 0 && secondChoice == thirdChoice);

if (isInvalid) {
return -2;
}

你代码中还有另一个bug,检查选择应该包括8和0:

if (choice >= 8 || choice <= 0) {
return -1;
}


<details>
<summary>英文:</summary>

Use this:

boolean isInvalid = firstChoice!=0 ?
(firstChoice == secondChoice ||firstChoice == thirdChoice):
(secondChoice!=0 && secondChoice==thirdChoice);

if(isInvalid) {
return -2;
}

Another bug in your code, check of choice should be inclusive of 8 and 0

if(choice >= 8 || choice =< 0){
return -1;
}



</details>



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  • 本文由 发表于 2020年8月7日 12:43:27
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