JVM MaxHeapSize := 0 – 这是什么意思?

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英文:

JVM MaxHeapSize := 0 - what does this mean?

问题

我看到这里有其他类似的问题:https://stackoverflow.com/questions/4667483/how-is-the-default-max-java-heap-size-determined 和 https://stackoverflow.com/questions/26631498/understanding-java-heap

我运行了命令来查看我的堆大小 java -XX:+PrintFlagsFinal -version,我得到了MaxHeapSize的输出:

uintx MaxHeapSize := 0 {product}

这是什么意思?

英文:

I have seen other questions on here like: https://stackoverflow.com/questions/4667483/how-is-the-default-max-java-heap-size-determined and https://stackoverflow.com/questions/26631498/understanding-java-heap

I run the command to see my heap size java -XX:+PrintFlagsFinal -version and I get the output for MaxHeapSize:

uintx MaxHeapSize := 0 {product}

What does this mean?

答案1

得分: 6

这是JDK 8中的一个bug。

MaxHeapSize在HotSpot源代码中被定义为uintx,代表64位无符号整数。

在JDK 8中,打印uintx标志值的格式是"%-16lu",它将输入视为unsigned long

然而,C++中unsigned long的大小在Windows和Unix上有所不同:

  • 大多数类Unix系统是LP64,其中unsigned long的大小为64位。
  • Windows上的Visual C++是LLP64,其中unsigned long的大小为32位。

因此,JDK 8在Windows上仅打印uintx标志的低32位。这就是为什么如果MaxHeapSize恰好是4 GiB的整数倍,你会看到uintx MaxHeapSize := 0。这只是打印错误;实际的最大堆大小是正确的。

这个bug在JDK 9中作为JDK-8042893更改的一部分被修复了:

} else if (is_uintx()) {
-      st->print("%-16lu", get_uintx());
+      st->print(UINTX_FORMAT_W(-16), get_uintx());
英文:

This is a bug in JDK 8.

MaxHeapSize is defined in HotSpot sources as uintx, which stands for 64-bit unsigned integer.

In JDK 8, the format for printing uintx flag values is "%-16lu", which treats input as unsigned long.

However, the size of C++ unsigned long differs on Windows and Unix:

  • Most Unix-like systems are LP64, where the size of unsigned long is 64 bit.
  • Visual C++ on Windows is LLP64, where the size of unsigned long is 32 bit.

So, JDK 8 on Windows prints only low 32 bits of uintx flags. That's why if MaxHeapSize is an exact multiple of 4 GiB, you'll see uintx MaxHeapSize := 0. This is just the printing error; the actual max heap size is correct.

The bug was fixed in JDK 9 as a part of JDK-8042893 change:

     } else if (is_uintx()) {
-      st->print("%-16lu", get_uintx());
+      st->print(UINTX_FORMAT_W(-16), get_uintx());

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  • 本文由 发表于 2020年8月7日 06:12:38
  • 转载请务必保留本文链接:https://go.coder-hub.com/63292471.html
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