英文:
How can I combine *\u" and the UTF-8 code for console output? (Java)
问题
我想将"\u"与包含Hex代码的String组合起来，以便我可以在控制台中打印出Unicode字符。
我尝试过类似这样的方法，但控制台只打印普通文本，例如\uf600：
ArrayList<String> arr = new ArrayList<String>();
emoji.codePoints()
.mapToObj(Integer::toHexString)
.forEach((n) -> arr.add(n)); // arr will contain hex strings
for (int i = 1; i < arr.size(); i += 2) {
System.out.println("\\u" + arr.get(i));
}
英文:
I would like to combine a "\u" with a String that contains a Hex-Code so that I can print out a unicode character in the console.
I've tried something like this, but the console only prints regular text, eg \uf600:
ArrayList<String> arr = new ArrayList<String>();
emoji.codePoints()
.mapToObj(Integer::toHexString)
.forEach((n) -> arr.add(n)); // arr will contain hex strings
for (int i = 1; i < arr.size(); i += 2) {
System.out.println("\\u" + arr.get(i));
}
答案1
得分: 2
在Java中，\u 仅存在于编译器中，作为一种便利方式，帮助你在源代码中添加Unicode字符字面量。如果在运行时创建一个包含 \u 后跟十六进制数字的字符串，没有机制可以将其转换为单个 char。
听起来你想将每个代码点分别转换为一个字符串。以下是一种可以实现的方法：使用 Character.toChars 将代码点转换为字符数组，然后从字符数组构建一个新的字符串：
ArrayList<String> arr = new ArrayList<String>();
emoji.codePoints().mapToObj(Character::toChars).map(String::new)
.forEach(arr::add)
英文:
In Java, \u exists only in the compiler, as a convenience to help you add unicode character literals in your source code. If at run time you create a string that contains \ u followed by hex digits, there is no mechanism in place to transform it into a single char.
It sounds like you want to transform each code point separately to a string. Here is one way you can do that: use Character.toChars to transform the code point to a char array, and then build a new string from the char array:
ArrayList<String> arr = new ArrayList<String>();
emoji.codePoints().mapToObj(Character::toChars).map(String::new)
.forEach(arr::add)
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