Java: Read a File & Split a line into separate string

I want to read a file, file.txt that contains word pairs like this...

yaniv:bobo

After reading this file.txt , I want to split this text and put each words in variables and try to compare them like this :

Scanner scan = new Scanner(new FileReader(file));
while(scan.hasNextLine()) {
 		  
     	  String descritpion = scan.nextLine();
     	  
     	  System.out.println("line" +descritpion);	
     	 
     	  String []temp = descritpion.split(":");   
 		 
     	  String name = temp[0];   
 		  String surname = temp[1];
 	 
 		 System.out.println("name : "+ name);	
 		 System.out.println("surname : "+ surname);
      
 	  		
 }

if(surname == "bobo") {
				System.out.println("date set from file ");
				GUI_view.getDateChooser().setDate( new SimpleDateFormat("yyyy-MM-dd").parse(part1) );
				}	

BUT I GET THIS ERROR ?? WHY ?? WHats Wrong ??

Exception in thread "AWT-EventQueue-0" 
java.lang.ArrayIndexOutOfBoundsException: 1
	at controller.TaskController.openFile(TaskController.java:213)
	at controller.TaskController.lambda$11(TaskController.java:110)
	at javax.swing.AbstractButton.fireActionPerformed(Unknown Source)
	at javax.swing.AbstractButton$Handler.actionPerformed(Unknown Source)
	at javax.swing.DefaultButtonModel.fireActionPerformed(Unknown Source)
	at javax.swing.DefaultButtonModel.setPressed(Unknown Source)

Don't know if this will fix your problem, but instead of

if(surname == "bobo") {

Use:

if(surname.contains("bobo")) {

surname == "bobo" will return false as its comparing the address of surname

Check how your file ends. Scanner is clever enough to throw away a single line-break from the end. However if there is anything (like a space or another line break) afterwards, that's going to be a new line to be read.
In such cases

> String descritpion = scan.nextLine();

will read an empty-ish string, then

> String []temp = descritpion.split(":");

splits it into a single-item array, where

> String name = temp[0];

contains the entire string (being empty or containing a single space or something), that's how it passes
but

> String surname = temp[1];

does not exist, and that's why it throws an exception.
However in such cases a line should appear on screen prior to the exception. See test (with strings instead of files) here: https://ideone.com/ixo0kd - the no-line-break, and single-line-break cases work fine, the space-after-line-break and double-line-break cases throw the exception, but have an empty line displayed before.