问题

public static void printPaths(RequestMapping mapping) {
    System.out.println(String.join(",", mapping.path()));
}

以下代码无法工作。有趣的是，堆栈溢出的回答者在驳斥之前不会仔细阅读问题。
```java
final GetMapping getMapping = method.getAnnotation(GetMapping.class);
printPaths(getMapping);

在我像这样使用时是否存在类型 X：

public static void printPaths(X mapping) {
    System.out.println(String.join(",", mapping.path()));
}

以下代码能够正常工作吗？

// WhateverMapping 表示它可以是 RequestMapping、GetMapping、PostMapping 等等......
final WhateverMapping whateverMapping = method.getAnnotation(WhateverMapping.class);
printPaths(whateverMapping);

非常感谢。

<details>
<summary>英文:</summary>

```java
    public static void printPaths(RequestMapping mapping) {
        System.out.println(String.join(&quot;,&quot;,mapping.path()));
    }

the following code cannot work. Interestingly, stack overflow respondents will not read the question carefully before disproving of it.

        final GetMapping getMapping = method.getAnnotation(GetMapping.class);
        printPaths(getMapping);

is there a type X when I use it like this:

    public static void printPaths(X mapping) {
        System.out.println(String.join(",",mapping.path()));
    }

the following code can work well?

        //WhateverMapping means it could be RequestMapping, or GetMapping, or PostMapping, or .....
        final WhateverMapping whateverMapping = method.getAnnotation(WhateverMapping.class);
        printPaths(whaterverMappingMapping);

Thanks a lot.

答案1

得分: 0

这是不可能的，因为@GetMapping是一个组合注释，没有超类。一种解决方法是仅使用@RequestMapping，因为@GetMapping只是@RequestMapping(method=GET)的快捷方式。

GetMapping映射 = 方法.getAnnotation(GetMapping.class);
System.out.println(映射 instanceof RequestMapping); // false

GetMapping mapping = method.getAnnotation(GetMapping.class);
System.out.println(mapping instanceof RequestMapping); // false