英文:
Is there an efficient way to detect if a string contains a substring which is in a large set of characteristic strings?
问题
例如，给定字符串 aaaaaaaaaXyz，我想要找出它是否包含在一个特征字符串集合 {'xy','xyz','zzz','cccc','dddd',....} 中的子字符串，该集合可能有一百万个成员。是否有一种高效的方法？
英文:
For example, given a string aaaaaaaaaXyz, I want to find out if it contains a substring which is in a characteristic string set {'xy','xyz','zzz','cccc','dddd',....}, which may have one million members. Is there an efficient way?
答案1
得分: 2
鉴于您的搜索集可能非常大，我建议只需迭代该集合并检查潜在的子字符串匹配：
public boolean containsSubstring(String input, Set<String> subs) {boolean match = false;for (String sub : subs) {if (input.contains(sub)) {match = true;break;}}return match;}
英文:
Given that your search set might be very large, I would recommend just iterating that set and checking for a potential substring match:
public boolean containsSubstring(String input, Set<String> subs) {boolean match = false;for (String sub : subs) {if (input.contains(sub)) {match = true;break;}}return match;}
答案2
得分: 2
首先，您准备好dictionary，就像这样：
Set<String> stringSet = Set.of("xy", "xyz", "zzz", "zzy", "cccc", "dddd");Map<Character, List<String>> dictionary = new HashMap<>();for (String word : stringSet)dictionary.computeIfAbsent(word.charAt(0), k -> new ArrayList<>()).add(word);System.out.println(dictionary);
输出：
{c=[cccc], d=[dddd], x=[xyz, xy], z=[zzy, zzz]}
然后，您可以使用以下方法来查找：
static boolean contains(String input, Map<Character, List<String>> dictionary) {for (int i = 0, max = input.length(); i < max; ++i) {char first = input.charAt(i);if (dictionary.containsKey(first))for (String word : dictionary.get(first))if (input.startsWith(word, i))return true;}return false;}
英文:
First of all, you prepare the dictionary. just like this
Set<String> stringSet = Set.of("xy", "xyz", "zzz", "zzy", "cccc", "dddd");Map<Character, List<String>> dictionary = new HashMap<>();for (String word : stringSet)dictionary.computeIfAbsent(word.charAt(0), k -> new ArrayList<>()).add(word);System.out.println(dictionary);
output:
{c=[cccc], d=[dddd], x=[xyz, xy], z=[zzy, zzz]}
And you can use this method to find out.
static boolean contains(String input, Map<Character, List<String>> dictionary) {for (int i = 0, max = input.length(); i < max; ++i) {char first = input.charAt(i);if (dictionary.containsKey(first))for (String word : dictionary.get(first))if (input.startsWith(word, i))return true;}return false;}
答案3
得分: 0
我找到了Aho-Corasick算法的Java实现，这正是我想要的。感谢Clashsoft的提示。
英文:
With the hint of Clashsoft,I found the java implementation of Aho-Corasick algorithm , which is the one i want ,thanks for Clashsoft
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