JavaScript JSON解析查询与MongoDB

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英文:

javascript json parsing query with mongodb

问题

I have a function which gets data from my mongodb database. I am trying to console log the result. I can see the result as

console.log(result);

This gives

[
  {
    _id: 5f2940b77e6f8b26e0726cb9,
    Val_String: '2',
    T1_String: '2162',
    T2_String: '2068',
    T3_String: '1950',
    T4_String: '1956',
    Pdiff_String: '-0.010000',
    Time_String: '2020-05-20 12:51:20 GMT',
    __v: 0
  }
]

However, when I do:

var T1 = result.T1_String;
console.log(T1);

I get undefined. So my question is how do I correctly parse this to get my data.

英文:

I have a function which gets data from my mongodb database. I am trying to console log the result. I can see the result as

console.log(result);

This gives

[
  {
    _id: 5f2940b77e6f8b26e0726cb9,
    Val_String: '2',
    T1_String: '2162',
    T2_String: '2068',
    T3_String: '1950',
    T4_String: '1956',
    Pdiff_String: '-0.010000',
    Time_String: '2020-05-20 12:51:20 GMT',
    __v: 0
  }
]

However, when I do:

var T1 = result.T1_String;
console.log(T1);

I get undefined. So my question is how do I correctly parse this to get my data.

答案1

得分: 1

你需要访问列表中的第一个对象。因此,

var T1 = result[0].T1_String;
console.log(T1);

将会输出 t1 字符串。

英文:

you have to access the first object in the list. Therefore

var T1 = result[0].T1_String;
console.log(T1);

will give the t1 string

答案2

得分: 1

结果返回一个对象数组,而不仅仅是一个单一对象。
通过方括号表示法 [] 访问这些对象。

var T1 = result[0].T1_String; //result[0] 是数组中的第一个对象
英文:

The result gives back an array of objects and not just a single object.
Access the objects by square bracket notation []

var T1 = result[0].T1_String; //result[0] is the first object in the array

huangapple
  • 本文由 发表于 2020年8月5日 16:52:57
  • 转载请务必保留本文链接:https://go.coder-hub.com/63261617.html
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