英文:
How to recursively call a function for a set period of time?
问题
我会翻译您提供的内容，不包括代码部分。以下是翻译好的部分：
我想在捕获到我的 IOException 时递归调用 run() 函数，但前提是该方法的总执行时间必须 <= 10 秒。我故意拼写错误了 google.com 链接，以便始终抛出并捕获 IOException，但似乎 run() 方法并没有成功递归调用。我在这里做错了什么？任何帮助将不胜感激，谢谢！
英文:
I would like to recursively call the run() function when my IOException is caught if and only if the total execution time for this method has been <= 10 seconds. I mistyped the google.com link purposely so that the IOException always gets thrown and caught but it seems like the run(); method isn't being successfully recursively called. What did I do wrong here? Any help would be appreciated, thanks!
@Overrideprotected void onCreate(Bundle savedInstanceState) {super.onCreate(savedInstanceState);setContentView(R.layout.activity_main);new Thread() {public void run() {Document doc;try {doc = Jsoup.connect("http://google.comt/").get();runOnUiThread( new Runnable(){public void run(){// do stuff}});} catch (IOException e) {e.printStackTrace();if (System.nanoTime() <= 10000000000L) { // 10 secondsrun(); // RECURSIVE CALL}}}}.start}
答案1
得分: 1
以下是已翻译的内容：
long startTime = System.currentTimeMillis();while (System.currentTimeMillis() - startTime <= 10000) {run();}
如果您想使用纳秒，您可以尝试如下：
long startTime = System.nanoTime();while (System.nanoTime() - startTime <= 10000000000) {run();}
英文:
long startTime = System.currentTimeMillis();while(System.currentTimeMillis() - startTime <= 10000){run();}
If you want use nano seconds, you can try as below:
long startTime = System.nanoTime();while(System.nanoTime() - startTime <= 10000000000){run();}
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