Does continue statement blocks the entire code below it, even if it is within if statement?

Here is my code.

    public class TwinPrimeNumbers {
    	
    	public static void main(String[] args) {
    		// TODO Auto-generated method stub
    		
    		boolean isTwinPrime = false;
    		int count = 0, countTwo = 0, countThree = 0;
    		
    		inner:
    		for (int i = 1; i <= 100; i++) {
    			
    			for (int j = 1; j <= ((i + 2) / 2); j++) { 
    				
    				if (i % j == 0) 
    					count++; 
    				
    				if ((i + 2) % j == 0)
    					countTwo++; // 1
    			}
    			
    			if (count >= 1 || countTwo >= 1) { // This part is having a problem.
    				continue inner;
    			}
    
    			else {
    				
    				for (int j = 1; j <= ((i + 1) / 2); j++) {
    					
    					if ((i + 1) % j == 0) {
    						countThree++;
    					}
    				}
    			}
    			isTwinPrime = (i + 2) - i == 2;
    
    			if ( isTwinPrime == true && countThree >= 2 && count == 1 && countTwo == 1)
    				System.out.printf("Twin Primes: ( %d, %d ) %n", i, (i + 2));
    			count = 0;
    			countTwo = 0;
    			countThree = 0;
    		}
    	}
    }

I'm having a problem when this statement appear on my code There is no output appearing in the console.
Does the continue statement blocks the other code below?

**if (count >= 1 || countTwo >= 1) {
	continue inner;
}**

Because there is no output appearing when I run the program.

continue statement skips the current iteration of the loop.

In your code, count >= 1 || countTwo >= 1 is true for each value of i, so continue statement executes in each iteration of the outer loop and as soon as continue statement executes, it jumps back to the start of the loop without ever executing the statements below. Eventually, loop's termination condition evaluates to false and hence the loop breaks.

There is absolutely no use of label in your case because without label, your code will execute in exactly the same manner as it is with the label.

Also your logic is all wrong. You can simplify your code as shown below:

public class TwinPrimeNumbers {
    static boolean isPrime(int n) { 
        if (n <= 1) return false; 
  
        for (int i = 2; i < n; i++) 
            if (n % i == 0) return false; 
  
        return true; 
    } 
    
    public static void main(String args[]) {
        int primeOne = -1;
        
        for (int i = 1; i <= 100; i++) {
            // if current number is prime and the differene between
            // previously saved prime number and current number is 2, 
            // then we have a pair of Twin Primes 
            if (i - primeOne == 2 && TwinPrimeNumbers.isPrime(i)) {
                System.out.printf("Twin Primes: ( %d, %d ) %n", primeOne, i);
                // update primeOne
                primeOne = i;
            }
            // if previous condition is false and current number is prime,
            // save it in primeOne variable 
            else if (TwinPrimeNumbers.isPrime(i)) {
                primeOne = i;
            }
        }
    }
}

output:

Twin Primes: ( 3, 5 ) 
Twin Primes: ( 5, 7 ) 
Twin Primes: ( 11, 13 ) 
Twin Primes: ( 17, 19 ) 
Twin Primes: ( 29, 31 ) 
Twin Primes: ( 41, 43 ) 
Twin Primes: ( 59, 61 ) 
Twin Primes: ( 71, 73 ) 

continue inner means to continue execution from the next iteration of the loop labeled inner, regardless of where this statement is (other than that it may appear only inside said loop).

Hello and welcome to StackOverflow!

continue's use case as a goto is not really encouraged as it represents an unconditional jump through the code.

In this case you can discard the label considering your continue statement is not included in more than one loop. The code becomes:

int count = 0, countTwo = 0, countThree = 0;
            
for (int i = 1; i <= 100; i++) {
   for (int j = 1; j <= ((i + 2) / 2); j++) {     
       if (i % j == 0) 
          count++; 
                    
       if ((i + 2) % j == 0)
          countTwo++; // 1
   }
   
   if (count >= 1 || countTwo >= 1) { // This part is having a problem.
      continue;
   }

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