解析Spring中的MultipartFile数据为字符串

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英文:

Parsing MultipartFile data to string in spring

问题

我正在尝试将MultipartFile数据解析为字符串,并在Java Spring Boot中将字符串作为响应返回。有人可以建议正确的方法吗?

**controller.java**

```java
@POST
@Path("/modelInfo")
@Produces({ "application/json" })
public Response getPretrainedModel(MultipartFile data) throws IOException {
    String content = new String(data.getBytes(), StandardCharsets.UTF_8);
    return Response.status(Response.Status.OK).entity(content).build();
}

file.json

{
  "documents": [
    {
      "id": "1",
      "text": "abc"
    }
  ]
}

我将file.json作为multipart/form-data的请求体发送,并希望读取文件内容并将其存储为字符串。


<details>
<summary>英文:</summary>

I am trying to parse the MultipartFile data to string and return the string as response in java springboot. Can anyone suggest the right approach for this?

**controller.java**

    @POST
    @Path(&quot;/modelInfo&quot;)
    @Produces({ &quot;application/json&quot; })
    public Response getPretrainedModel(MultipartFile data) throws IOException {
        String content = new String(data.getBytes(), StandardCharsets.UTF_8);
        return Response.status(Response.Status.OK).entity(content).build();
    }


**file.json**

    {
      &quot;documents&quot;: [
        {
          &quot;id&quot;: &quot;1&quot;,
          &quot;text&quot;: &quot;abc&quot;
        }
      ]
    }

I am sending file.json in request body as multipart/form-data and I want to read the content of the file and store it as string.

</details>


# 答案1
**得分**: 0

如果你正在使用Spring和Spring Boot,那么你不应该使用错误的注解。Spring不支持`Jax-RS`规范。因此,请将你的注解更改为以下内容:

```java
@PostMapping(value = "/modelInfo", produces = MediaType.APPLICATION_JSON_VALUE)

然后,要返回一个对象,你可以在方法中直接返回该对象:

@PostMapping(value = "/modelInfo", produces = MediaType.APPLICATION_JSON_VALUE)
public String getPretrainedModel(@RequestParam("file") MultipartFile data) throws IOException {
    String content = new String(data.getBytes(), StandardCharsets.UTF_8);
    return content;
}

注意:

  • 不要忘记在方法参数中添加@RequestParam注解以获取上传的文件。属性名file必须与你的POST请求中上传的属性名相同。
  • 默认情况下,如果你没有告诉Spring发送其他内容,HTTP响应代码为200。
  • 如果你想要覆盖这一点,请在方法上添加@ResponseStatus注解。
英文:

If you are using Spring and Spring Boot, then you are not using the proper annotation. Spring does not support Jax-RS specification. Therefor, change your annotations for this one:

//    @POST
//    @Path(&quot;/modelInfo&quot;)
//    @Produces({ &quot;application/json&quot; })
@PostMapping(value = &quot;/modelInfo&quot;, produces = MediaType.APPLICATION_JSON_VALUE)

Then, to return an object, you can just return the object in the method:

@PostMapping(value = &quot;/modelInfo&quot;, produces = MediaType.APPLICATION_JSON_VALUE)
public String getPretrainedModel(@RequestParam(&quot;file&quot;) MultipartFile data) throws IOException {
    String content = new String(data.getBytes(), StandardCharsets.UTF_8);
    return content;
}

Note:

  • Don't forget to add the annotation @RequestParam in your method parameter to get the uploaded file. The name file must be the name of the attribute uploaded by your POST request
  • By default, the HTTP Response is 200 when you don't tell Spring to send something else.
  • If you want to override that, annotate your method with @ResponseStatus

huangapple
  • 本文由 发表于 2020年8月4日 17:52:21
  • 转载请务必保留本文链接:https://go.coder-hub.com/63244337.html
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