URL regex match with and without query strings

I need a regex which could match the following string under below mentioned condition

https://example.com/jobs/2273/software-engineer/job?mobile=true&width=760

Ans: True

https://example.com/jobs/2273/software-engineer/job

Ans:True

https://example.com/jobs/2273/software-engineer/job?mobile=true

Ans: False (should contain both key values as in #1

In short the regex should match the url if it end upto job as in #2 else if it contains some parameters then it must contain mobile=true and width both must be present and additional parameters are accepted.

You don't need a regular expression. Use the methods in class java.net.URL, namely getPath() and getQuery().

According to your question, the string returned by method getPath() should end with job and method getQuery() should either return null or a string that contains both mobile= and width=

/* import java.net.URL */
URL url = new URL("whatever"); // replace 'whatever' with your actual URL
String path = url.getPath();
if (path.endsWith("job")) {
    String query = url.getQuery();
    if (query == null || (query.contains("mobile=") && query.contains("width=")) {
        // valid
    }
}

Use the regex, (?:.*\/job\?(mobile=(?:true|false)&width=\d+))|(?:.*\/job\?(width=\d+&mobile=(?:true|false)))|.*job(?!.)

Check this for a quick demo and explanation.

Demo using Java code:

public class Main {
	public static void main(String[] args) {
		// Test URL strings
		String[] urls = { "https://example.com/jobs/2273/software-engineer/job?mobile=true&width=760",
				"https://example.com/jobs/2273/software-engineer/job?mobile=false&width=760",
				"https://example.com/jobs/2273/software-engineer/job?width=760&mobile=true",
				"https://example.com/jobs/2273/software-engineer/job?width=760&mobile=false",
				"https://example.com/jobs/2273/software-engineer/job",
				"https://example.com/jobs/2273/software-engineer/job?mobile=true" };

		String regex = "(?:.*\\/job\\?(mobile=(?:true|false)&width=\\d+))|(?:.*\\/job\\?(width=\\d+&mobile=(?:true|false)))|.*job(?!.)";

		for (String s : urls) {
			System.out.println(s + " => " + s.matches(regex));
		}
	}
}

Output:

https://example.com/jobs/2273/software-engineer/job?mobile=true&width=760 => true
https://example.com/jobs/2273/software-engineer/job?mobile=false&width=760 => true
https://example.com/jobs/2273/software-engineer/job?width=760&mobile=true => true
https://example.com/jobs/2273/software-engineer/job?width=760&mobile=false => true
https://example.com/jobs/2273/software-engineer/job => true
https://example.com/jobs/2273/software-engineer/job?mobile=true => false

Try this regex:

.+\/job\b(\?mobile=true\&width=\d+)?$

Please check the demo

In Java this must be written something like this:

String regex = ".+\\/job\\b(\\?mobile=true\\&width=\\d+)?$";