返回的翻译部分:需要一个能够将数组相乘并在数组为空时返回0的代码。

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英文:

Need code that multiplies arrays, and returns 0 if array is empty

问题

Here is the translated code:

我需要一个代码它会将由测试形成的数组内容相乘

public void testMulArray() {
    FirstSteps firstSteps = new FirstSteps();
    int[] array1 = {1, 2, 3};
    assertEquals(6, firstSteps.mul(array1));
    int[] array2 = {-1, -2, 3};
    assertEquals(6, firstSteps.mul(array2));
    int[] array3 = {1, 2, 0};
    assertEquals(0, firstSteps.mul(array3));
    int[] array4 = {};
    assertEquals(0, firstSteps.mul(array4));
}

在此之前,我编写了一个类似的代码,用于返回由测试形成的数组内容的总和

public void testSumArray() {
    FirstSteps firstSteps = new FirstSteps();
    int[] array1 = {1, 2, 3};
    assertEquals(6, firstSteps.sum(array1));
    int[] array2 = {-1, -2, 3};
    assertEquals(0, firstSteps.sum(array2));
    int[] array3 = {};
    assertEquals(0, firstSteps.sum(array3));
}

求和的代码为

public class FirstSteps {
    public int sum(int[] array){
        int sum = 0;
        for (int value : array) {
            sum += value;
        }
        return sum;
    }
}

这段代码已经起作用,为了实现相乘,我编写了类似的代码

public class FirstSteps {
    public int mul(int[] array){
        int mul = 1;  // 注意这里初始化为1,而不是0
        for (int value : array) {
            mul *= value;
        }
        return mul;
    }
}
英文:

I need code that multiplies array contents which are formed by test

public void testMulArray() {
    FirstSteps firstSteps = new FirstSteps();
    int[] array1 = {1, 2, 3};
    assertEquals(6, firstSteps.mul(array1));
    int[] array2 = {-1, -2, 3};
    assertEquals(6, firstSteps.mul(array2));
    int[] array3 = {1, 2, 0};
    assertEquals(0, firstSteps.mul(array3));
    int[] array4 = {};
    assertEquals(0, firstSteps.mul(array4));
}

Before this, I made a similar code that returns the sum of array contents that is formed by the test

public void testSumArray() {
    FirstSteps firstSteps = new FirstSteps();
    int[] array1 = {1, 2, 3};
    assertEquals(6, firstSteps.sum(array1));
    int[] array2 = {-1, -2, 3};
    assertEquals(0, firstSteps.sum(array2));
    int[] array3 = {};
    assertEquals(0, firstSteps.sum(array3));
}

Code for sum is

public class FirstSteps {
    public int sum(int[] array){
        int sum = 0;
        for (int value : array) {
            sum += value;
        }
        return sum;
    }
}

It worked and for multiplying I made similar code

public class FirstSteps {
    public int mul(int[] array){
        int mul = 0;
        for (int value : array) {
            mul *= value;
        }
        return mul;
    }
}

答案1

得分: 0

你将 mul = 0,但是,零乘以任何数都等于零!

相反,你应该将初始值设为 mul = 1

public class FirstSteps {
    public int mul(int[] array){
        if (array.length == 0) return 0;
        int mul = 1; 
        for (int value : array) {
            mul *= value;
        }
        return mul;
    }
}
英文:

You make mul = 0, but, zero multiplies by any number results zero!

Instead you should make that initial value mul = 1.

public class FirstSteps {
    public int mul(int[] array){
        if (array.length == 0) return 0;
        int mul = 1; 
        for (int value : array) {
            mul *= value;
        }
        return mul;
    }
}

huangapple
  • 本文由 发表于 2020年8月3日 17:50:19
  • 转载请务必保留本文链接:https://go.coder-hub.com/63227200.html
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