问题

在我的一个方法中：

public void pageIsReady()

实现是：

Awaitility.await().atMost(5, TimeUnit.SECONDS).until(isPageLoaded());

这里，isPageLoaded() 方法返回一个布尔值，但我希望它返回一个 Callable 的布尔值，因为 Awaitility 中的 until() 方法需要一个 Callable<Boolean>。

请帮助我将 isPageLoaded() 方法修改为返回 Callable<Boolean>。

以下是 isPageLoaded() 方法的实现：

protected Callable<Boolean> isPageLoaded() {
    String jsQuery = "function pageLoaded() "
            + "{var loadingStatus=(document.readyState=='complete');"
            + "return loadingStatus;};"
            + "return pageLoaded()";

    return () -> {
        try {
            Boolean isSuccess = (Boolean) evaluateJavascript(jsQuery);
            return isSuccess;
        } catch (Exception exp) {
            exp.printStackTrace();
            return false;
        }
    };
}

public void pageIsReady()

Awaitility.await().atMost(5, TimeUnit.SECONDS).until(isPageLoaded());

protected Boolean isPageLoaded() {
    String jsQuery = "function pageLoaded() "
            + "{var loadingStatus=(document.readyState=='complete');"
            + "return loadingStatus;};"
            + "return pageLoaded()";

    boolean isSuccess = false;
    try {
        isSuccess = (Boolean) evaluateJavascript(jsQuery);
    } catch (Exception exp) {
        exp.printStackTrace();
    }
    return isSuccess;
}

答案1

得分: 1

以下是翻译好的部分：

最简单的方法是使用方法引用 Callable<Boolean> isPageLoaded = this::isPageLoaded，或者显式地将其用作 Lambda 表达式 Callable<Boolean> isPageLoaded = () -> isPageLoaded();

这会看起来像这样：

Awaitility.await().atMost(5, TimeUnit.SECONDS).until(this::isPageLoaded);
Awaitility.await().atMost(5, TimeUnit.SECONDS).until(() -> isPageLoaded());

另一种方法是将您的方法定义为返回 Callable<Boolean>，然后使用 Lambda 语法 () -> {} 来编写可调用对象。

protected Callable<Boolean> isPageLoaded() {
    return () -> {
        String jsQuery = "function pageLoaded() "
            + "{var loadingStatus=(document.readyState=='complete');"
            + "return loadingStatus;};"
            + "return pageLoaded()";

        boolean isSuccess = false;
        try {
            isSuccess = (Boolean) evaluateJavascript(jsQuery);
        } catch (Exception exp) {
            exp.printStackTrace();
        }
        return isSuccess;
    };
}

Lambda 表达式和方法引用可以是非常强大的工具。

<details>
<summary>英文:</summary>

The easiest way to do that is to use a method reference `Callable&lt;Boolean&gt; isPageLoaded = this::isPageLoaded`, or to use it explicitly as lambda `Callable&lt;Boolean&gt; isPageLoaded = () -&gt; isPageLoaded();`

This would look like

    Awaitility.await().atMost(5, TimeUnit.SECONDS).until(this::isPageLoaded);
    Awaitility.await().atMost(5, TimeUnit.SECONDS).until(() -&gt; isPageLoaded());

Another way would be to define your method as returning a `Callable&lt;Boolean&gt;` and then using lambda syntax `() -&gt; {}` to write the callable.

    protected Callable&lt;Boolean&gt; isPageLoaded() {
        return () -&gt; {
            String jsQuery = &quot;function pageLoaded() &quot;
                + &quot;{var loadingStatus=(document.readyState==&#39;complete&#39;);&quot;
                + &quot;return loadingStatus;};&quot;
                + &quot;return pageLoaded()&quot;;
    
            boolean isSuccess = false;
            try {
                isSuccess = (Boolean) evaluateJavascript(jsQuery);
            } catch (Exception exp) {
                exp.printStackTrace();
            }
            return isSuccess;
        };
    }

Lambda expressions and method references can be quite powerful tools.

</details>



# 答案2
**得分**: 0

只需将您的 `isPageLoaded()` 方法定义如下：

    protected Callable&lt;Boolean&gt; isPageLoaded() {
        //代码...
    }

<details>
<summary>英文:</summary>

Just define your `isPageLoaded()` method as follows:

    protected Callable&lt;Boolean&gt; isPageLoaded() {
        //code..
    }

</details>