在Java中的模式打印问题:“框架”,由符号‘.’和‘*’组成,尺寸为AxB

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英文:

Pattern printing problem in java: “frame" composed out of the symbols ‘.’ and ‘*’, dimensions AxB

问题

Here's the translated code for the second task:

static void second(int a, int b) {
    for (int i = 1; i <= a * b; i++) {
        for (int j = 1; j <= a; j++) {
            for (int k = 1; k <= b; k++) {
                if (j == 1 || j == a || k == 1 || k == b) {
                    System.out.print("*");
                } else {
                    System.out.print(".");
                }
            }
            System.out.print(" ");
        }
        System.out.println();
    }
}

This code will generate the desired pattern for the given values of "a" and "b" in the second task.

英文:

Write a program that reads natural numbers a and b and prints a “frame” composed of the symbols ‘.’ and ‘*’ dimensions axb as below (dots are inside and stars around the dots):

a=4,b=4;  a=3,b=1
****     *
*..*     *
*..*     *
****

I solved it this way:

static void first(int a, int b) {
	for(int i=1; i&lt;=a; i++) {
		for(int j=1; j&lt;=b;j++) {
			if (i==1 || i==a || j==1 || j==b)
				System.out.print(&quot;*&quot;);
			else System.out.print(&quot;.&quot;);
		}
		System.out.println();
	}
}

The next task is a bit different, here is what a program should return for given a and b:

a=3,b=1     
**** 
*..*
*..*
****
*..*
*..*
****
*..*
*..*
****


a=4,b=4
*************
*..*..*..*..*
*..*..*..*..*
*************
*..*..*..*..*
*..*..*..*..*
*************
*..*..*..*..*
*..*..*..*..*
*************
*..*..*..*..*
*..*..*..*..*
*************

I do not know how to do this one, when I tried using the first method as a help method I just get a messy pattern..

答案1

得分: 2

如果你考虑一下,* 总是用于第 3*i 个元素,其中 i 的范围从 0a*3。对于列也是类似的:它总是用于第 3*j 个元素,其中 j 的范围从 0b*j。所有其他元素都是 .

你可以通过使用模运算 (%) 来简单地表示这个结构:

class Main {
	
	static void print(int a, int b) {
		for (int row = 0; row <= a*3; row++) {
			for (int col = 0; col <= b*3; col++) {
				if (row % 3 == 0) {
					System.out.print("*");
				}
				else if (col % 3 == 0) {
					System.out.print("*");
				}
				else {
					System.out.print(".");
				}
			}
			System.out.print("\n");
		}
	}
	
	
	public static void main(String args[]) {
		print(3, 1);
		print(4, 4);
	}
}
英文:

If you think about it, a * is always used for the 3*ith element in a row where i ranges from 0 to a*3. It's similar for the columns: it's always the 3*jth element in a col where j ranges from 0 to b*j. All other elements are .s.

You can express this structure simply by using the modulo operation (%):

class Main {
	
	static void print(int a, int b) {
		for (int row = 0; row &lt;= a*3; row++) {
			for (int col = 0; col &lt;= b*3; col++) {
				if (row % 3 == 0) {
					System.out.print(&quot;*&quot;);
				}
				else if (col % 3 == 0) {
					System.out.print(&quot;*&quot;);
				}
				else {
					System.out.print(&quot;.&quot;);
				}
			}
			System.out.print(&quot;\n&quot;);
		}
	}
	
	
	public static void main(String args[]) {
		print(3, 1);
		print(4, 4);
	}
}

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  • 本文由 发表于 2020年8月1日 01:10:07
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