英文:
Regarding date format in java
问题
public class DatePgm {
public static void main(String[] args) throws ParseException {
SimpleDateFormat sdf=new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss+SS:SZ");
Date date1 = sdf.parse("2020-07-26T18:52:24+05:30");
System.out.println("DATE="+sdf.format(date1));
}
}
请注意，我已经将您提供的代码中的HTML实体代码（如"）替换为原始的引号字符。
英文:
public class DatePgm {
public static void main(String[] args) throws ParseException {
SimpleDateFormat sdf=new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss'+'SS:SZ");
Date date1 = sdf.parse("2020-07-26T18:52:24+05:30");
System.out.println("DATE="+sdf.format(date1));
}
}
Can any one help me to print the exact date and time format "2020-07-26T18:52:24+05:30"
答案1
得分: 2
tl;dr ⇒ java.time.OffsetDateTime
In this case, you don't really need to define a format/formatter yourself. The default DateTimeFormatter of an OffsetDateTime (which appears suitable here) is able to parse (and print/format) your example String. You can do it as follows:
public static void main(String[] args) {
// your example datetime String
String datetime = "2020-07-26T18:52:24+05:30";
// parse the String to an OffsetDateTime using the default formatter
OffsetDateTime odt = OffsetDateTime.parse(datetime);
// and print the OffsetDateTime using its default formatter
System.out.println("DATE=" + odt);
}
the output is
DATE=2020-07-26T18:52:24+05:30
英文:
tl;dr ⇒ java.time.OffsetDateTime
In this case, you don't really need to define a format/formatter yourself. The default DateTimeFormatter of an OffsetDateTime (which appears suitable here) is able to parse (and print/format) your example String. You can do it as follows:
public static void main(String[] args) {
// your example datetime String
String datetime = "2020-07-26T18:52:24+05:30";
// parse the String to an OffsetDateTime using the default formatter
OffsetDateTime odt = OffsetDateTime.parse(datetime);
// and print the OffsetDateTime using its default formatter
System.out.println("DATE=" + odt);
}
the output is
DATE=2020-07-26T18:52:24+05:30
答案2
得分: 1
使用Instant而不是Date。Instant支持带有时区的日期时间。
Instant date1 = Instant.parse("2020-07-26T18:52:24+05:30");
System.out.println("DATE= " + date1);
英文:
Use Instant instead of Date. Instant supports date time with zone
Instant date1 = Instant.parse("2020-07-26T18:52:24+05:30");
System.out.println("DATE= " + date1);
答案3
得分: 1
你可以尝试以下代码：
String string = "2020-07-26T18:52:24+05:30";
OffsetDateTime odt = OffsetDateTime.parse(string);
System.out.println(odt);
英文:
You can try following,
String string = "2020-07-26T18:52:24+05:30";
OffsetDateTime odt = OffsetDateTime.parse( string );
System.out.println(odt);
答案4
得分: 0
你可以使用 Calendar 来获取日期：
String time = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss'+SS:SZ'").format(Calendar.getInstance().getTime());
英文:
You can use Calendar to get the date:
String time = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss'+'SS:SZ").format(Calendar.getInstance().getTime());
答案5
得分: 0
我认为你应该使用LocalDateTime，来自Java 8。大多数格式的很好示例都可以在这里找到。
英文:
I think you should use LocalDatetIme, from java 8. A very good example for most of the formats are available here
答案6
得分: 0
使用SimpleDateFormat，您需要设置时区（Asia/Colombo为+05:30）：
SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ssXXX");
Date date1 = sdf.parse("2020-07-26T18:52:24+05:30");
sdf.setTimeZone(TimeZone.getTimeZone("Asia/Colombo"));
System.out.println("DATE=" + sdf.format(date1));
输出结果：
DATE=2020-07-26T18:52:24+05:30
英文:
With SimpleDateFormat you have to set the timzone(Asia/Colombo is +05:30):
SimpleDateFormat sdf=new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ssXXX");
Date date1 = sdf.parse("2020-07-26T18:52:24+05:30");
sdf.setTimeZone(TimeZone.getTimeZone("Asia/Colombo"));
System.out.println("DATE="+sdf.format(date1));
Output:
DATE=2020-07-26T18:52:24+05:30
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