英文:
Java String... question regarding multiple inputs for a method
问题
可以创建一个类，并拥有一个名为String ... 的属性，它可以接受任意数量的字符串，无论多少都可以。
示例：
请原谅我的粗略伪代码，这是针对Java的。
// 这是方法：
public void getXXXX(String ...) {
// 随机代码在循环中执行，输入的字符串数量可以随意
}
// 这是调用它的代码
getXXXX("Benjamin", "Jordan", "Steve")
getXXXX("Pengu", "No")
getXXXX("hi")
英文:
is it possible to create a class and have a String ... attribute that takes as many or as little strings as you put?
example:
please excuse my rough pseudocode, this is for java.
//this is the method:
public void getXXXX(String ...) {
//random code executes in a loop with as many as strings that are inputted
}
//this code calls it
getXXXX("Benjamin","Jordan","Steve")
getXXXX("Pengu","No")
getXXXX("hi")
答案1
得分: 2
是的，你输入的基本上可以工作，你只需要在类型后面添加一个参数名称。
class StringDecorator {
public static String join(final String... strings) {
final var builder = new StringBuilder();
for (final var string : strings) {
builder.append(string);
}
return builder.toString();
}
}
然后在某个地方调用它：
StringDecorator.join("Hello, ", "World!"); // "Hello, World!"
英文:
Yes, what you entered will more or less work, you just need a parameter name after your type.
class StringDecorator {
public static String join(final String... strings) {
final var builder = new StringBuilder();
for (final var string : strings) {
builder.append(string);
}
return builder.toString();
}
}
Then invoke this somewhere
StringDecorator.join("Hello, ", "World!"); // "Hello, World!"
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