Not able to convert string to int, not able to get length of array element in java

I have a String amount having value 496988,(11874),952743,(35175),33425,(654)

I'm splitting it so I can get individual element in String[] casesDataArr

String[] casesDataArr = textView.getText().toString().split(" ");

Now I just need the integers from array and remove the ( , )

I tried this

active = Integer.parseInt(casesDataArr[0]);
delActive = Integer.parseInt(casesDataArr[1].substring(1, casesDataArr.length));

discharged = Integer.parseInt(casesDataArr[2]);
delDischarged = Integer.parseInt(casesDataArr[3].substring(1, casesDataArr.length));

death = Integer.parseInt(casesDataArr[4]);
delDeath = Integer.parseInt(casesDataArr[5].substring(1, casesDataArr.length));

but getting error in last line:
> java.lang.StringIndexOutOfBoundsException: length=5; index=6

I know it's due to the casesDataArr.length but when I write casesDataArr[5].length it shows redundant text. I'm missing something do guide me. Having any doubts comment below.

3 issues:

• You are using the legnth of the array instead of the length of each string. What should have lead you to this is that you use the same length for each index, isn't that weird?)

• The index of the last character of a String is not string.length()but string.length() -1 as index starts from 0.

• You don't use casesDataArr[1] but use casesDataArr[0] twice

  active = Integer.parseInt(casesDataArr[0]);
  delActive = Integer.parseInt(casesDataArr[1].substring(1, casesDataArr[1].length()-1));
  
  discharged = Integer.parseInt(casesDataArr[2]);
  delDischarged = Integer.parseInt(casesDataArr[3].substring(1, casesDataArr[3].length()-1));
  
  death = Integer.parseInt(casesDataArr[4]);
  delDeath = Integer.parseInt(casesDataArr[5].substring(1, casesDataArr[5].length()-1));
  

Using regex, you can remove non-numeric characters:

String input = "496988,(11874),952743,(35175),33425,(654)";

List<Integer> values = new ArrayList<>();
for (String s : input.split(",")) {
    values.add(Integer.parseInt(s.replaceAll("\\D", "")));
}

System.out.println("values: " + values);

Result:

> values: [496988, 11874, 952743, 35175, 33425, 654]

Given: String of value : 496988,(11874),952743,(35175),33425,(654)

First remove ",":

String casesDataArr[]=textView.getText().toString().split(",");

Your array is now as follows:

index 0: 496988

index 1: (11874)

index 2: 952743

index 3: (35175)

index 4: 33425

index 5: (654)

Second, remove "()" if present:

for(int i=0;i<casesDataArr.length;i++){

if(casesDataArr[i].contains("(")&&casesDataArr[i].contains(")")){
casesDataArr[i]=casesDataArr[i].substring(casesDataArr[i].indexOf("(")+1,casesDataArr[i].indexOf(")"));
}

}

The obtained array is:

index 0: 496988

index 1: 11874

index 2: 952743

index 3: 35175

index 4: 33425

index 5: 654

To fetch a number in the int type from an index of the array, just write this:

int myInteger=Integer.parseInt(casesDataArr[0]);