条件循环在Java中

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英文:

Condition for loops in java

问题

我有2个循环。

第一个:

while (part[i].compareToIgnoreCase(part[i-1]) < 0) {
    smaller = myarr[i];
    myarr[i] = myarr[i-1];
    myarr[i-1] = smaller;
    i--;
    if (i <= 0) {
        break;
    }
}

第二个:

while (Integer.parseInt(part[i]) < Integer.parseInt(part[i-1])) {
    smaller = myarr[i];
    myarr[i] = myarr[i-1];
    myarr[i-1] = smaller;
    i--;
    if (i <= 0) {
        break;
    }
}

如果您注意到,这两个循环执行相同的任务,只是条件不同。这些条件不能同时传递,只能一次使用一个条件(因为这些循环是方法的一部分,分别传入了两个内容不同的字符串数组)。

我可以将这两个循环合并在一起,并做些什么,以便一次只选择一个条件吗?

英文:

I have 2 loops.

The first:

while(part[i].compareToIgnoreCase(part[i-1])&lt;0) {
    smaller = myarr[i];
    myarr[i] = myarr[i-1];
    myarr[i-1] = smaller;
    i--;
    if(i&lt;=0) {
    break;
}

The second:

while(Integer.parseInt(part[i]) &lt; Integer.parseInt(part[i-1])) {
    smaller = myarr[i];
    myarr[i] = myarr[i-1];
    myarr[i-1] = smaller;
    i--;
    if(i&lt;=0) {
    break;
}

If you notice, both the loops perform the same task. Just the conditions are different. The conditions can not be passed in together i.e.only one can be used at a time.(Because these loops are a part of a method and 2 String arrays with different content are passed in.)

Can I somehow merge both of these together and do something so that only one condition is picked up at a time?

答案1

得分: 0

听起来你是在询问如何将一个Predicate(确切地说是BiPredicate<String, String>)作为参数传递。

  public void bubbleSort(String[] part, BiPredicate<String, String> predicate) {
    while(predicate.test(part[i], part[i-1])) {
      // 进行冒泡排序操作
    }
  }

  public void bubbleSort(String[] part) {
    if (isText) {
      bubbleSort(part, (l, r) -> l.compareToIgnoreCase(r) < 0);
    } else {
      bubbleSort(part, (l, r) -> Integer.parseInt(l) < Integer.parseInt(r));
    }
  }

尽管如此,有更好的方法来对数组进行排序! 条件循环在Java中

Arrays.sort(part, String::compareToIgnoreCase); // 按文本排序
Arrays.sort(part, Comparator.comparingInt(Integer::parseInt)); // 按数字排序
英文:

Sounds like you are asking how to take a Predicate (BiPredicate&lt;String, String&gt; to be precise) as a parameter.

  public void bubbleSort(String[] part, BiPredicate&lt;String, String&gt; predicate) {
    while(predicate.test(part[i], part[i-1])) {
      // Do bubblesort stuff
    }
  }

  public void bubbleSort(String[] part) {
    if (isText) {
      bubbleSort(part, (l, r) -&gt; l.compareToIgnoreCase(r) &lt; 0);
    } else {
      bubbleSort(part, (l, r) -&gt; Integer.parseInt(l) &lt; Integer.parseInt(r));
    }
  }

That said there are better ways to sort arrays! 条件循环在Java中

Arrays.sort(part, String::compareToIgnoreCase); // Sort by text
Arrays.sort(part, Comparator.comparingInt(Integer::parseInt)); // Sort by number

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  • 本文由 发表于 2020年7月28日 07:24:18
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