英文:
Java string manipulation x number of lines with y element
问题
以下是您提供的内容的翻译：
示例
x=3 y=3
用户输入：
101
100
000
然后如何将字符串分离以将每个值输入不同的单元格。
编辑 1:
import java.util.Scanner;
public class RedVsGreen {
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
int x, y;
String line;
String[] lineVector = new String[3];
while (lineVector.length != 2 || (Integer.parseInt(lineVector[0]) >= 1000 || Integer.parseInt(lineVector[0]) <= 1)
|| (Integer.parseInt(lineVector[1]) <= 1 || Integer.parseInt(lineVector[1]) >= 1000)) {
System.out.print("请输入x和y，用逗号分隔（大于1且小于1000）：");
// 读取x和y
line = scanner.nextLine();
// 通过逗号分隔所有值
lineVector = line.split("\\s*,\\s*");
}
// 解析值为整数
x = Integer.parseInt(lineVector[0]);
y = Integer.parseInt(lineVector[1]);
for (int i = 0; i < x; i++) {
}
}
}
请注意，代码中可能存在其他错误，需要根据具体需求进行调试和修复。
英文:
Easiest way to explain my problem is to give you an example. Lets say I have 2 values X and Y. I wan't to ask the user to enter X lines with Y elements and they should be only 0s and 1s and then enter that values in array.
Example
x=3 y=3
User input:
101
100
000
And then how to separate string to enter each value in different cell.
EDIT 1:
import java.util.Scanner;
public class RedVsGreen {
public static void main(String[] args) {
Scanner scanner=new Scanner(System.in);
int x,y;
String line;
String[] lineVector = new String[3];
while ( lineVector.length !=2 || (Integer.parseInt(lineVector[0]) >= 1000 || Integer.parseInt(lineVector[0]) <= 1)
|| (Integer.parseInt(lineVector[1]) <= 1 || Integer.parseInt(lineVector[1]) >= 1000)){
System.out.print("Please enter x and y, comma separated (more than 1 and less than 1000):");
//read x,y
line = scanner.nextLine();
//separate all values by comma
lineVector = line.split("\\s*,\\s*");
}
//parsing the values to Integer
x = Integer.parseInt(lineVector[0]);
y = Integer.parseInt(lineVector[1]);
for (i = 0 ; i < x; i++){
}
//
// int[][] field = new int[x][y];
// for (int row = 0; row < field.length; row++) {
// System.out.println("");
// for (int col = 0; col < field[row].length; col++) {
// field[row][col] = 9; //dummy value
// System.out.print(field[row][col] + " ");
// }
// }
//
}
}
答案1
得分: 1
**接收 x 和 y**
在这个问题中，你的 while 条件过于复杂。使用 do while 格式更适合，因为你至少会获取一次值，而且代码更可读。
另外，你可以使用 x 来代替 `Integer.parseInt(lineVector[0])`（y 也是同样的道理），而不是重复这个过程，这样可以缩短条件判断。
```java
String line;
String[] lineVector;
int x = -1, y = -1;
do {
System.out.print("请输入 x 和 y，以逗号分隔（大于1且小于1000）：");
line = scanner.nextLine();
lineVector = line.split("\\s*,\\s*");
if (lineVector.length != 2)
continue;
x = Integer.parseInt(lineVector[0]);
y = Integer.parseInt(lineVector[1]);
} while (!((x > 1 && x < 1000 && y > 1 && y < 1000)));
首先，我删除了 lineVector 的初始值，因为在这种情况下初始化是不必要的（你之前需要这样做是因为它出现在 while 条件中）。
我将 x 和 y 初始化为 -1（任何不在我们范围内的数字都可以），以确保 do-while 条件在为这两个数字提供适当值之前得到满足。
检查二进制值的函数
创建一个函数来检查字符串值是否为二进制。
public static boolean isBinary(String s) {
for (int i = 0; i < s.length(); ++i) {
char c = s.charAt(i);
if (c != '0' && c != '1')
return false;
}
return true;
}
接收二进制值
String[] binaries = new String[x];
System.out.println("输入长度为 " + y + " 的二进制值：");
// 获取二进制值
for (int i = 0; i < x; ++i) {
binaries[i] = scanner.nextLine();
while (!isBinary(binaries[i]) || binaries[i].length() != y) {
System.out.println("无效的二进制值。请重新输入新值：");
binaries[i] = scanner.nextLine();
}
}
接收二进制值，并在无效时继续要求输入。
填充二维数组
int[][] field = new int[x][y];
for (int i = 0; i < x; ++i) {
System.out.println();
for (int j = 0; j < y; ++j) {
char c = binaries[i].charAt(j);
if (c == '0')
field[i][j] = 0;
else
field[i][j] = 1;
System.out.print(field[i][j] + " ");
}
}
在这里，Integer.parseInt 是不必要的，因为只有两个可能的值（0 和 1）。
<details>
<summary>英文:</summary>
**Receiving x and y**
while ( lineVector.length !=2 ...)
Your while condition is too complicated, a do while format matches this problem much better since you are going to get the values at least once, and the code is more readable.
Also you could have used x instead of `Integer.parseInt(lineVector[0])` (same for y) instead of repeating the process, this would have shortened the condition.
String line;
String[] lineVector;
int x = -1, y = -1;
do {
System.out.print("Please enter x and y, comma separated (more than 1 and less than 1000):");
line = scanner.nextLine();
lineVector = line.split("\\s*,\\s*");
if(lineVector.length != 2)
continue;
x = Integer.parseInt(lineVector[0]);
y = Integer.parseInt(lineVector[1]);
} while (!((x > 1 && x < 1000 && y > 1 && y < 1000)));
First of all I removed the initial value of `lineVector` as it is unnecessary to initialize it in this case (you needed to do it because of it being present in your while condition).
I initialized `x` and `y` to -1 (Any number not in our range would work) in order to make sure the do-while condition is fulfilled until proper values are offered for both of the numbers.
**Function to check binary values**
Create a function to check if string values are binary.
public static boolean isBinary(String s) {
for(int i = 0; i < s.length(); ++i) {
char c = s.charAt(i);
if(c != '0' && c != '1')
return false;
}
return true;
}
**Receive binaries**
String[] binaries = new String[x];
System.out.println("Enter binaries with length " + y + " :");
//Get binaries
for(int i = 0; i < x; ++i) {
binaries[i] = scanner.nextLine();
while(!isBinary(binaries[i]) || binaries[i].length() != y) {
System.out.println("Invalid binary value. Re-enter new value:");
binaries[i] = scanner.nextLine();
}
}
Receive binary values and continue asking if invalid.
**Filling the 2D array**
int[][] field = new int[x][y];
for(int i = 0; i < x; ++i) {
System.out.println();
for(int j = 0; j < y; ++j) {
char c = binaries[i].charAt(j);
if(c == '0')
field[i][j] = 0;
else
field[i][j] = 1;
System.out.print(field[i][j] + " ");
}
}
`Integer.parseInt` is not necessary here as there are only two possible values (0 and 1)
</details>
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