I want to extract all substring that match regex pattern from a String and store them in a String array

I want to extract all the substrings that have Exceptions. For example, "SQLException", "SQLSyntaxErrorException" etc from the below string, and store those values in a String array. How do I go about it? I tried to use the split(regex) method but that stores everything else in the array but not those exceptions. Help is appreciated.

public static void exceptionsOutOfString(){
    String input = "org.hibernate.exception.SQLException: error executing work org.hibernate.exception.SQLGrammarException: error \n" +
            "executing work     at  ~[hibernate-core-5.0.12.Final.jar:5.0.12.Final]     \n" +
            "\\norg.hibernate.exception.SQLGrammarException: error executing work     at  ~[hibernate-core-5.0.12.Final.jar:5.0.12.Final] \n" +
            "     Caused by: java.sql.SQLSyntaxErrorException: malformed string: 'Acme''    at";

    String regex = ".[a-zA-Z]*Exception";

    String[] exceptions  = input.split(regex);

Try this:

String input = <exception list...>
String regex = "\\w+Exception";
Matcher m = Pattern.compile(regex).matcher(input);

while (m.find()) {
	System.out.println(m.group());
}

Prints

SQLException
SQLGrammarException
SQLGrammarException
SQLSyntaxErrorException

To put them in an array, do the following:

String[] array = m.results()
             .map(MatchResult::group)
             .toArray(String[]::new);

m.results() produces a stream of MatchResults. So take that and use the group method to get the string then return an array.

As was astutely observed by Abra, the above was not introduced until release JDK 9.

Here is an alternative.

List<String> list = new ArrayList<>();
while (m.find()) {
	 list.add(m.group());
}

Then either use as a list or convert.

String[] array = list.stream().toArray(String[]::new);
// or
String[] array = list.toArray(String[]::new); // JDK 11