英文:
Jax rs resources 404 not found errror
问题
我在使用Java的jax-rs运行应用程序时遇到以下错误：
HTTP状态404 - 未找到
类型状态报告
消息 /ajavaeeconcurrency/resources/greetUser
描述 原始服务器未找到目标资源的当前表示，或不愿透露该资源的存在。
Apache Tomcat/9.0.30
我正在使用Java 8，尝试使用jax-rs创建REST API。
以下是代码：
package com.app.rest;
import javax.ws.rs.ApplicationPath;
import javax.ws.rs.core.Application;
@ApplicationPath("resources")
public class JAXRSConfiguration extends Application {
}
以下是资源类：
package com.app.rest;
import javax.ws.rs.GET;
import javax.ws.rs.Path;
@Path("/greetUser")
public class GreetResource {
@GET
public String greetUser() {
return "java EE concurrency starts.";
}
}
这是我的 pom.xml：
<project xmlns="http://maven.apache.org/POM/4.0.0"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/xsd/maven-4.0.0.xsd">
<modelVersion>4.0.0</modelVersion>
<groupId>com.mycompany</groupId>
<artifactId>ajavaeeconcurrency</artifactId>
<version>0.0.1-SNAPSHOT</version>
<packaging>war</packaging>
<dependencies>
<dependency>
<groupId>javax</groupId>
<artifactId>javaee-api</artifactId>
<version>8.0</version>
<scope>provided</scope>
</dependency>
<dependency>
<groupId>org.eclipse.microprofile</groupId>
<artifactId>microprofile</artifactId>
<version>2.0.1</version>
<type>pom</type>
<scope>provided</scope>
</dependency>
</dependencies>
<build>
<finalName>ajavaeeconcurrency</finalName>
</build>
<properties>
<maven.compiler.source>1.8</maven.compiler.source>
<maven.compiler.target>1.8</maven.compiler.target>
<failOnMissingWebXml>false</failOnMissingWebXml>
</properties>
</project>
我的 artifactId 是 ajavaeeconcurrency。我尝试使用以下 URI 访问资源：
GET http://localhost:8080/ajavaeeconcurrency/resources/greetUser
但我收到了 404 错误。我应该如何解决这个问题？
英文:
I am getting below error while running application in java using jax-rs
HTTP Status 404 – Not Found
Type Status Report
Message /ajavaeeconcurrency/resources/greetUser
Description The origin server did not find a current representation for the target resource or is not willing to disclose that one exists.
Apache Tomcat/9.0.30
I am using java8 and trying to create restAPI using jax-rs
Below is the code
package com.app.rest;
import javax.ws.rs.ApplicationPath;
import javax.ws.rs.core.Application;
@ApplicationPath("resources")
public class JAXRSConfiguration extends Application {
}
Below is resource class
package com.app.rest;
import javax.ws.rs.GET;
import javax.ws.rs.Path;
@Path("/greetUser")
public class GreetResource {
@GET
public String greetUser()
{
return "java EE concurrency starts.";
}
This is my pom.xml
<project xmlns="http://maven.apache.org/POM/4.0.0"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/xsd/maven-4.0.0.xsd">
<modelVersion>4.0.0</modelVersion>
<groupId>com.mycompany</groupId>
<artifactId>ajavaeeconcurrency</artifactId>
<version>0.0.1-SNAPSHOT</version>
<packaging>war</packaging>
<dependencies>
<dependency>
<groupId>javax</groupId>
<artifactId>javaee-api</artifactId>
<version>8.0</version>
<scope>provided</scope>
</dependency>
<dependency>
<groupId>org.eclipse.microprofile</groupId>
<artifactId>microprofile</artifactId>
<version>2.0.1</version>
<type>pom</type>
<scope>provided</scope>
</dependency>
</dependencies>
<build>
<finalName>ajavaeeconcurrency</finalName>
</build>
<properties>
<maven.compiler.source>1.8</maven.compiler.source>
<maven.compiler.target>1.8</maven.compiler.target>
<failOnMissingWebXml>false</failOnMissingWebXml>
</properties>
</project>
My artifactId is ajavaeeconcurrency . I am trying to access resource using below URI
GET http://localhost:8080/ajavaeeconcurrency/resources/greetUser
I am getting 404 error. How can I resolve the same
答案1
得分: 1
我认为你的URL是http://localhost:8080/resources/greetUser。
URL中的artifactId部分通常在应用服务器中配置，如果有需要的话。
英文:
I think your URL is http://localhost:8080/resources/greetUser.
URL with artifactId part usually configuried in application server if it need.
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