如何在Java中检查一个二维点是否位于二维多边形内?

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英文:

How to check if a 2d point is inside a 2D polygon in Java?

问题

在我的Java应用程序中,我使用顶点数组创建2D多边形。例如,我想使用以下4个顶点创建一个简单的正方形:

[-130, -74], [-125, -74], [-125, -70], [-130, -70]

然后,我想要检查一个点是否在生成的多边形内。但是,如果我检查例如这个点:

[-125, -73]

使用 polygon.contains(x, z) ,它会判断该点不在多边形内。即使我检查一个角落,比如 [-125, -74] ,它也返回false。我感到困惑的是,如果我检查这个点 [-126, -74] ,它却返回true。所以有些点实际上被视为在多边形内,而另一些点则不是,我无法理解其中的原因。这是我设置的一个用于测试的示例代码,其中没有特殊之处:

public static void main(String[] args) {
   Polygon polygon = new Polygon(new int[]{-130, -125, -125, -130}, new int[]{-74, -74, -70, -70}, 4);
   System.out.println("" + polygon.contains(-125, -73));
   System.out.println("" + polygon.contains(-125, -74));
   System.out.println("" + polygon.contains(-126, -74));
}

输出也是这样的:

false
false
true

我还要指出这只是一个简单的示例,但多边形可能是一个非常复杂的形状,例如像这样的疯狂形状:

如何在Java中检查一个二维点是否位于二维多边形内?

英文:

In my Java application I'm creating 2D polygons using an array of vertices. For example, I want to create a simple square using these 4 vertices

[-130, -74], [-125, -74], [-125, -70], [-130, -70]

Then I want to check if a point is inside the generated Polygon. But if I check, for example, this point

[-125, -73]

using polygon.contains(x, z) it says is not inside the Polygon. Even if I check a corner, like [-125, -74] is returns false. The strange part for me is that is I check this point [-126, -74] is returns true, so some points are actually seen as inside the polygon, while others are not, and I can't understand why is it. This is a sample code I set up to test this, nothing special about it

public static void main(String[] args) {
   Polygon polygon = new Polygon(new int[]{-130, -125, -125, -130}, new int[]{-74, -74, -70, -70}, 4);
   System.out.println("" + polygon.contains(-125, -73));
   System.out.println("" + polygon.contains(-125, -74));
   System.out.println("" + polygon.contains(-126, -74));
}

And the output as well

false
false
true

I would also point out the fact that this is just a simple example, but the Polygon could be a really complex shape, for example something crazy like this

如何在Java中检查一个二维点是否位于二维多边形内?

答案1

得分: 2

这份文档中提到:

> 这个多边形使用奇偶绕组规则进行定义。参见WIND_EVEN_ODD以获取奇偶绕组规则的定义。

> WIND_EVEN_ODD<br>
> 用于指定用奇偶规则来确定路径内部的绕组规则常数。奇偶规则指出,如果从一个点引出的射线在任意方向上延伸至无穷远,与路径线段相交的次数为奇数,则该点位于路径内部。

你可以像这样进行操作。

static Polygon mirror(Polygon p) {
    int npoints = p.npoints;
    int[] xpoints = new int[npoints];
    int[] ypoints = new int[npoints];
    for (int i = 0; i < npoints; ++i) {
        xpoints[i] = -p.xpoints[i];
        ypoints[i] = -p.ypoints[i];
    }
    return new Polygon(xpoints, ypoints, npoints);
}

static boolean onVertex(Polygon p, int x, int y) {
    int npoints = p.npoints;
    for (int i = 0; i < npoints; ++i)
        if (p.xpoints[i] == x && p.ypoints[i] == y)
            return true;
    return false;
}

static boolean contains(Polygon p, int x, int y) {
    return p.contains(x, y)
        || onVertex(p, x, y)
        || mirror(p).contains(-x, -y);
}

以及

Polygon polygon = new Polygon(new int[]{-130, -125, -125, -130}, new int[]{-74, -74, -70, -70}, 4);
System.out.println("" + contains(polygon, -125, -73));
System.out.println("" + contains(polygon, -125, -74));
System.out.println("" + contains(polygon, -126, -74));

输出:

true
true
true

一个带洞的多边形测试。

int width = 100, height = 100;
BufferedImage image = new BufferedImage(width, height, BufferedImage.TYPE_INT_RGB);
int[] xs = {20, 80, 80, 20, 20, 40, 60, 60, 40, 40};
int[] ys = {20, 20, 80, 80, 20, 40, 40, 60, 60, 40};
Polygon p = new Polygon(xs, ys, xs.length);
Graphics2D g = image.createGraphics();
try (Closeable c = () -> g.dispose()) {
    g.setColor(Color.WHITE);
    g.fillRect(0, 0, width, height);
    g.setColor(Color.BLACK);
    g.drawPolygon(p);
    g.setColor(Color.RED);
    for (int x = 0; x < width; ++x)
        for (int y = 0; y < height; ++y)
            if (contains(p, x, y))
                g.fillRect(x, y, 1, 1);
}
ImageIO.write(image, "png", new File("data/testPolygon.png"));

输出为图像文件 "testPolygon.png"。

如果 contains(p, x, y) -> p.contains(x, y),则:

如何在Java中检查一个二维点是否位于二维多边形内?

英文:

The document Polygon says

> This Polygon is defined with an even-odd winding rule. See WIND_EVEN_ODD for a definition of the even-odd winding rule.

> WIND_EVEN_ODD<br>
> The winding rule constant for specifying an even-odd rule for determining the interior of a path. The even-odd rule specifies that a point lies inside the path if a ray drawn in any direction from that point to infinity is crossed by path segments an odd number of times.

So you can do like this.

static Polygon mirror(Polygon p) {
    int npoints = p.npoints;
    int[] xpoints = new int[npoints];
    int[] ypoints = new int[npoints];
    for (int i = 0; i &lt; npoints; ++i) {
        xpoints[i] = -p.xpoints[i];
        ypoints[i] = -p.ypoints[i];
    }
    return new Polygon(xpoints, ypoints, npoints);
}

static boolean onVertex(Polygon p, int x, int y) {
    int npoints = p.npoints;
    for (int i = 0; i &lt; npoints; ++i)
        if (p.xpoints[i] == x &amp;&amp; p.ypoints[i] == y)
            return true;
    return false;
}

static boolean contains(Polygon p, int x, int y) {
    return p.contains(x, y)
        || onVertex(p, x, y)
        || mirror(p).contains(-x, -y);
}

And

Polygon polygon = new Polygon(new int[]{-130, -125, -125, -130}, new int[]{-74, -74, -70, -70}, 4);
System.out.println(&quot;&quot; + contains(polygon, -125, -73));
System.out.println(&quot;&quot; + contains(polygon, -125, -74));
System.out.println(&quot;&quot; + contains(polygon, -126, -74));

output:

true
true
true

A test for a polygon with a hole.

int width = 100, height = 100;
BufferedImage image = new BufferedImage(width, height, BufferedImage.TYPE_INT_RGB);
int[] xs = {20, 80, 80, 20, 20, 40, 60, 60, 40, 40};
int[] ys = {20, 20, 80, 80, 20, 40, 40, 60, 60, 40};
Polygon p = new Polygon(xs, ys, xs.length);
Graphics2D g = image.createGraphics();
try (Closeable c = () -&gt; g.dispose()) {
    g.setColor(Color.WHITE);
    g.fillRect(0, 0, width, height);
    g.setColor(Color.BLACK);
    g.drawPolygon(p);
    g.setColor(Color.RED);
    for (int x = 0; x &lt; width; ++x)
        for (int y = 0; y &lt; height; ++y)
            if (contains(p, x, y))
                g.fillRect(x, y, 1, 1);
}
ImageIO.write(image, &quot;png&quot;, new File(&quot;data/testPolygon.png&quot;));

output

如何在Java中检查一个二维点是否位于二维多边形内?

If contains(p, x, y) -> p.contains(x, y) then

如何在Java中检查一个二维点是否位于二维多边形内?

答案2

得分: 1

从点P(x, y)发射一条射线,并计算与边界的相交情况,如果相交计数为奇数,则P在多边形内。

然而,如果射线与其中一个顶点相交,由于舍入问题可能难以确定相交点。因此,您可以按照以下步骤操作:

  • 以任意方向发射射线,使射线不直接命中任何顶点。
  • 对多边形中的每条边确定射线是否与边相交,如果是-增加计数器。
  • 在检查完所有边之后,如果交点计数为奇数,则P在内部。

https://en.wikipedia.org/wiki/Point_in_polygon

英文:

Shoot a ray from point P(x, y) and count for intersection with the edges, if intersection count is odd, then P is inside polygon.

However if ray intersects with one of the vertices it might be difficult to determine intersection point due to rounding problem. Therefore you may follow these steps:

  • Shoot a ray in any direction, such that the ray does not directly hit any vertices.
  • For each edge in polygon determine whether the ray intersects the edge, if yes - increase counter
  • After all edges have been checked, P inside if intersection counter is odd.

https://en.wikipedia.org/wiki/Point_in_polygon

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  • 本文由 发表于 2020年7月24日 06:03:52
  • 转载请务必保留本文链接:https://go.coder-hub.com/63063773.html
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