英文:
Json to Spring Expression mapping exception
问题
以下是您要的翻译内容：
当我尝试发起一个包含以下请求主体的POST请求（来自Postman），我遇到了映射异常：
> 类型定义错误：[简单类型，类org.springframework.expression.spel.support.ReflectiveMethodResolver]；嵌套异常为com.fasterxml.jackson.databind.exc.InvalidDefinitionException：找不到类org.springframework.expression.spel.support.ReflectiveMethodResolver的序列化器，也没有发现创建BeanSerializer的属性（为避免异常，请禁用SerializationFeature.FAIL_ON_EMPTY_BEANS）（通过引用链：com.freddiemac.security.policy.Policy["accessPolicies"]->java.util.ArrayList[0]->com.freddiemac.security.policy.AccessPolicy["condition"]->org.springframework.expression.spel.standard.SpelExpression["evaluationContext"]->org.springframework.expression.spel.support.StandardEvaluationContext["methodResolvers"]->java.util.ArrayList[0]）
POST调用 - 请求主体：
{
"accessPolicies": [{
"policyId": 1,
"resource": [
"/my-resource"
],
"action": [
"POST"
],
"condition": "#claims['userRoles'].contains('developer')"，// 这在Java中被映射为Spring表达式
"effect": "Allow"
}]
}
POJO类：
private String policyId;
private List<String> resource;
private List<String> action;
private List<String> role;
private Expression condition; // 从org.springframework.expression.Expression导入；
请问您是否需要其他帮助？提前感谢您的回复。
英文:
When I try to make a POST request (from postman) which has request body as below, I am facing mapping exception :
> Type definition error: [simple type, class org.springframework.expression.spel.support.ReflectiveMethodResolver]; nested exception is com.fasterxml.jackson.databind.exc.InvalidDefinitionException: No serializer found for class org.springframework.expression.spel.support.ReflectiveMethodResolver and no properties discovered to create BeanSerializer (to avoid exception, disable SerializationFeature.FAIL_ON_EMPTY_BEANS) (through reference chain: com.freddiemac.security.policy.Policy["accessPolicies"]->java.util.ArrayList[0]->com.freddiemac.security.policy.AccessPolicy["condition"]->org.springframework.expression.spel.standard.SpelExpression["evaluationContext"]->org.springframework.expression.spel.support.StandardEvaluationContext["methodResolvers"]->java.util.ArrayList[0])
POST call - Request Body :
{
"accessPolicies": [{
"policyId": 1,
"resource": [
"/my-resource"
],
"action": [
"POST"
],
"condition": "#claims['userRoles'].contains('developer')", // this is mapped as Spring expression in java
"effect": "Allow"
}]
}
POJO class :
private String policyId;
private List<String> resource;
private List<String> action;
private List<String> role;
private Expression condition; // import from : org.springframework.expression.Expression;
Could you please help me on this. Thanks in advance.
答案1
得分: 0
Expression接口没有序列化程序，因此接收String，而String具有有效的序列化程序。
然后，您可以使用SpelExpressionParser将String解析为有效的Expression。
class PostRequestDto {
private String serviceId;
private String version;
private List<AccessPolicy> accessPolicies;
// 省略了为了简洁性而省略的getter和setter方法
}
class AccessPolicy {
private String policyId;
private List<String> resource;
private List<String> action;
private List<String> role;
private String condition; // 在接收 SpEL 表达式时使用 String 序列化程序
private String effect;
// 省略了为了简洁性而省略的getter和setter方法
// 将接收到的 String 解析为 SpEL 表达式
public Expression getConditionExpression() {
// 为了简洁性，省略了适当的错误处理
ExpressionParser expressionParser = new SpelExpressionParser();
return expressionParser.parseExpression( this.condition );
}
}
英文:
Expression interface doesn't have serializer, so receive String instead, which does have valid serializer.
Then you can use SpelExpressionParser to parse String into a valid Expression.
class PostRequestDto {
private String serviceId;
private String version;
private List<AccessPolicy> accessPolicies;
// Getters and setters omitted for brevity
}
class AccessPolicy {
private String policyId;
private List<String> resource;
private List<String> action;
private List<String> role;
private String condition; // utilize String serializer when accepting SpEL Expression
private String effect;
// Getters and setters omitted for brevity
// parse received String to derive SpEL Expression
public Expression getConditionExpression() {
// proper error handling omitted for brevity
ExpressionParser expressionParser = new SpelExpressionParser();
return expressionParser.parseExpression( this.condition );
}
}
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