Scanner loop breaks + Regex issue

This task is whether a word is a palindrome, and I use java 11.

After entering of the word with spaces the code gives me an answer, but while loop breaks and the code "finishes with exit code 0" If I choose word = sc.next(). But If I write word = sc.nextLine() - It executes well and begins loop again.

I can't understand why, cause I can't debug this part of code, It's just skipped. And I don't understand why this happens. So can somebody explain to me what am I doing wrong?

Maybe there's a way to avoid this spaces?

P.S. I'm new to programming. Thanks to everyone.

    try {
Pattern pattern = Pattern.compile("[Y|y][E|e][S|s]");
while (true) {
String word = "";
Scanner sc = new Scanner(System.in);
System.out.println("Enter the word without spaces");
if (sc.hasNext("(?>\\p{Alpha})+")) {
word = sc.next(); 
System.out.println(word);
System.out.println("The word is correct");
String text2;
StringBuilder sb = new StringBuilder();
text2 =  sb.append(word).reverse().toString();
if (word.equalsIgnoreCase(text2)) {
System.out.println("Yes, it's a palindrome." + " " + "Want to try another one?");
System.out.println("Enter yes if you want to continue" + " or " + "enter any symbol if no");
if (sc.hasNext(pattern)) {
}
else {
break;
}
}
else {
System.out.println("No, it's not a palindrome." + " " + "Want to try another one?");
System.out.println("Enter yes if you want to continue" + " or " + "enter any symbol if no");
if (sc.hasNext(pattern)) {
}
else {
break;
}
}
}
else {
word = sc.next();
System.out.println("It's not a word");
System.out.println("Want to try another one?");
System.out.println("Enter yes if you want to continue" + " or " + "enter any symbol if no");
if (sc.hasNext(pattern)) {
}
else {
break;
}
}
}
}
catch (NoSuchElementException ex) {
System.out.println(ex.getMessage());
}
}

What can you improve in your regex, [Y|y][E|e][S|s]?

Use [Yy][Ee][Ss] instead. The [] specifies a character class and all the characters inside it mean one of them i.e. by default they come with an implicit OR. Check this to learn more about it.

How can you determine if the input contains space?

Pass " " to the function, String#contains to determine it.

Demo:

import java.util.Scanner;
public class Main {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
while (true) {
System.out.print("Enter a word without spaces: ");
String word = sc.nextLine();
if (word.contains(" ")) {
System.out.println("It's not a word");
} else {
System.out.println("The word is correct");
StringBuilder reverse = new StringBuilder(word).reverse();
System.out.println(word.equalsIgnoreCase(reverse.toString()) ? "Palindrome" : "Not a palindrome");
}
System.out.println("Want to try another one?");
System.out.print("Enter yes if you want to continue or any other symbol otherwise: ");
if (!sc.nextLine().matches("[Yy][Ee][Ss]")) {
break;
}
}
}
}

A sample run:

Enter a word without spaces: Hello World
It's not a word
Want to try another one?
Enter yes if you want to continue or any other symbol otherwise: yes
Enter a word without spaces: HELLO
The word is correct
Not a palindrome
Want to try another one?
Enter yes if you want to continue or any other symbol otherwise: YES
Enter a word without spaces: Malayalam
The word is correct
Palindrome
Want to try another one?
Enter yes if you want to continue or any other symbol otherwise: Yes
Enter a word without spaces: papa
The word is correct
Not a palindrome
Want to try another one?
Enter yes if you want to continue or any other symbol otherwise: n