英文:
Assert an Exception is Thrown in
问题
我在我的项目中有这个JUnit测试：
public class CalculatorBookingTest {private CalculatorBooking calculatorBooking;@Rulepublic ExpectedException expectedException = ExpectedException.none();@Beforepublic void setUp() {calculatorBooking = new CalculatorBooking();}@Testpublic void shouldThrowAnException_When_InputIsNull() {calculatorBooking.calculate(null, null, 0, null);expectedException.expect(CalculationEngineException.class);expectedException.expectMessage("Error");}}
但当我运行这个测试时，异常被抛出，但测试仍然失败。
英文:
I have this Junit test in my project
public class CalculatorBookingTest {private CalculatorBooking calculatorBooking;@Rulepublic ExpectedException expectedException = ExpectedException.none();@Beforepublic void setUp() {calculatorBooking = new CalculatorBooking();}@Testpublic void shouldThrowAnException_When_InputIsNull() {calculatorBooking.calculate(null, null, 0, null);expectedException.expect(CalculationEngineException.class);expectedException.expectMessage("Error");}}
but when I run the test, the Exception is Thrown but nevertheless the test fail
答案1
得分: 2
你可以这样做：
@Test(expected = CalculationEngineException.class)public void shouldThrowAnException_When_InputIsNull() {calculatorBooking.calculate(null, null, 0, null);}
从 Junit 文档 中：
> Test 注解支持两个可选参数。第一个参数 expected 声明了一个测试方法应该抛出一个异常。如果它没有抛出异常，或者抛出了一个不同于声明的异常，测试将失败。
英文:
You could do something like:
@Test(expected = CalculationEngineException.class)public void shouldThrowAnException_When_InputIsNull() {calculatorBooking.calculate(null, null, 0, null);}
From Junit doc :
> The Test annotation supports two optional parameters. The first,
> expected, declares that a test method should throw an exception. If it
> doesn't throw an exception or if it throws a different exception than
> the one declared, the test fails.
答案2
得分: 0
将会抛出异常的调用之前，请放置 expectedException.expect。
@Testpublic void shouldThrowAnException_When_InputIsNull() {expectedException.expect(CalculationEngineException.class);expectedException.expectMessage("Error");calculatorBooking.calculate(null, null, 0, null);}
英文:
Place expectedException.expect before the call that will throw the exception.
@Testpublic void shouldThrowAnException_When_InputIsNull() {expectedException.expect(CalculationEngineException.class);expectedException.expectMessage("Error");calculatorBooking.calculate(null, null, 0, null);}
答案3
得分: 0
你需要首先告诉JUnit该方法预计会抛出异常。然后，当异常被抛出时，它知道测试通过了。在你的代码中，你在异常被抛出后才放置了expect()，所以执行根本不会到那一步。正确的方式是：
@Testpublic void shouldThrowAnException_When_InputIsNull() {expectedException.expect(CalculationEngineException.class);expectedException.expectMessage("Error");calculatorBooking.calculate(null, null, 0, null);}
英文:
You need to first tell JUnit that the method is expected to throw the exception. Then when it's thrown - it knows that the test passes. In your code you put expect() after the exception is thrown - so the execution doesn't even go that far. The right way:
@Testpublic void shouldThrowAnException_When_InputIsNull() {expectedException.expect(CalculationEngineException.class);expectedException.expectMessage("Error");calculatorBooking.calculate(null, null, 0, null);}
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