英文:
Assert an Exception is Thrown in
问题
我在我的项目中有这个JUnit测试:
public class CalculatorBookingTest {
private CalculatorBooking calculatorBooking;
@Rule
public ExpectedException expectedException = ExpectedException.none();
@Before
public void setUp() {
calculatorBooking = new CalculatorBooking();
}
@Test
public void shouldThrowAnException_When_InputIsNull() {
calculatorBooking.calculate(null, null, 0, null);
expectedException.expect(CalculationEngineException.class);
expectedException.expectMessage("Error");
}
}
但当我运行这个测试时,异常被抛出,但测试仍然失败。
英文:
I have this Junit test in my project
public class CalculatorBookingTest {
private CalculatorBooking calculatorBooking;
@Rule
public ExpectedException expectedException = ExpectedException.none();
@Before
public void setUp() {
calculatorBooking = new CalculatorBooking();
}
@Test
public void shouldThrowAnException_When_InputIsNull() {
calculatorBooking.calculate(null, null, 0, null);
expectedException.expect(CalculationEngineException.class);
expectedException.expectMessage("Error");
}
}
but when I run the test, the Exception is Thrown but nevertheless the test fail
答案1
得分: 2
你可以这样做:
@Test(expected = CalculationEngineException.class)
public void shouldThrowAnException_When_InputIsNull() {
calculatorBooking.calculate(null, null, 0, null);
}
从 Junit 文档 中:
> Test 注解支持两个可选参数。第一个参数 expected 声明了一个测试方法应该抛出一个异常。如果它没有抛出异常,或者抛出了一个不同于声明的异常,测试将失败。
英文:
You could do something like:
@Test(expected = CalculationEngineException.class)
public void shouldThrowAnException_When_InputIsNull() {
calculatorBooking.calculate(null, null, 0, null);
}
From Junit doc :
> The Test annotation supports two optional parameters. The first,
> expected, declares that a test method should throw an exception. If it
> doesn't throw an exception or if it throws a different exception than
> the one declared, the test fails.
答案2
得分: 0
将会抛出异常的调用之前,请放置 expectedException.expect
。
@Test
public void shouldThrowAnException_When_InputIsNull() {
expectedException.expect(CalculationEngineException.class);
expectedException.expectMessage("Error");
calculatorBooking.calculate(null, null, 0, null);
}
英文:
Place expectedException.expect
before the call that will throw the exception.
@Test
public void shouldThrowAnException_When_InputIsNull() {
expectedException.expect(CalculationEngineException.class);
expectedException.expectMessage("Error");
calculatorBooking.calculate(null, null, 0, null);
}
答案3
得分: 0
你需要首先告诉JUnit该方法预计会抛出异常。然后,当异常被抛出时,它知道测试通过了。在你的代码中,你在异常被抛出后才放置了expect()
,所以执行根本不会到那一步。正确的方式是:
@Test
public void shouldThrowAnException_When_InputIsNull() {
expectedException.expect(CalculationEngineException.class);
expectedException.expectMessage("Error");
calculatorBooking.calculate(null, null, 0, null);
}
英文:
You need to first tell JUnit that the method is expected to throw the exception. Then when it's thrown - it knows that the test passes. In your code you put expect()
after the exception is thrown - so the execution doesn't even go that far. The right way:
@Test
public void shouldThrowAnException_When_InputIsNull() {
expectedException.expect(CalculationEngineException.class);
expectedException.expectMessage("Error");
calculatorBooking.calculate(null, null, 0, null);
}
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