在方括号内突出显示文本(正则表达式?)Android Kotlin

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英文:

Highlight text within square bracket (regex ?) Android kotlin

问题

我想突出显示所有位于方括号内的子字符串,例如:“[Toto] is [doing a lot of] stuff at the same time。”
我知道如何提取它。
我知道如何突出显示:

val str = SpannableString("Toto is doing a lot of stuff at the same time.")
str.setSpan(BackgroundColorSpan(Color.YELLOW), 0, 4, 0)
str.setSpan(BackgroundColorSpan(Color.YELLOW), 8, 22 , 0)
textView.text = str

但问题是我不知道如何同时实现两者。

显然,我想要在应用高亮效果之后删除方括号,但当我执行toString()然后执行replace()时,高亮效果被移除。

另外,高亮是基于索引的,我不想提取子字符串,而是保留在原始字符串中,我不知道应该通过哪种优化的方式来实现这一点。

这是结果:
在方括号内突出显示文本(正则表达式?)Android Kotlin

英文:

I would like to highlight all of the substring which are inside square brackets, ex: "[Toto] is [doing a lot of] stuff at the same time."
I know how to extract it.
I know how to highlight:

val str = SpannableString("Toto is doing a lot of stuff at the same time.")
str.setSpan(BackgroundColorSpan(Color.YELLOW), 0, 4, 0)
str.setSpan(BackgroundColorSpan(Color.YELLOW), 8, 22 , 0)
textView.text = str

But the problem is I don't know how to achieve both together.

I obviously want to remove the square bracket after have applied the highlight effect but when I do a toString() then a replace() the highlight is removed.

Also, the highlight is made with index, and I don't want to extract the substring but let it in the original string, I don't know by which optimized way I should achieve that.

There is the result:
在方括号内突出显示文本(正则表达式?)Android Kotlin

答案1

得分: 4

也许最好不使用 regex 来提取括号之间的文本。我认为这会增加这项任务的复杂性。通过对文本进行简单的迭代,我们可以以线性复杂度获得结果。

val text = "[Toto] is [doing a lot of] stuff at the same time."

val spanStack = Stack<Pair<Int, Int>>()
var index = 0

text.forEach {
    when (it) {
        '[' -> spanStack.push(index to index)
        ']' -> spanStack.push(spanStack.pop().first to index)
        else -> index++
    }
}

val spannableString = text
    .replace("[\\[\\]]".toRegex(), "")
    .let { SpannableString(it) }
    .apply {
        spanStack.forEach {
            setSpan(
                BackgroundColorSpan(Color.YELLOW),
                it.first,
                it.second,
                SpannableString.SPAN_INCLUSIVE_INCLUSIVE
            )
        }
    }

textView.text = spannableString

结果:

<tr>
    <td><img src="https://i.stack.imgur.com/xDdRE.png" width="300"/></td>
</tr>
英文:

Maybe it's better not to use regex in order to extract the texts between close brackets. I think it increases the complexity of this job. Using a simple iteration over the text, we can achieve the result in linear complexity.

val text = &quot;[Toto] is [doing a lot of] stuff at the same time.&quot;

val spanStack = Stack&lt;Pair&lt;Int, Int&gt;&gt;()
var index = 0

text.forEach {
    when (it) {
        &#39;[&#39; -&gt; spanStack.push(index to index)
        &#39;]&#39; -&gt; spanStack.push(spanStack.pop().first to index)
        else -&gt; index++
    }
}

val spannableString = text
    .replace(&quot;[\\[\\]]&quot;.toRegex(), &quot;&quot;)
    .let { SpannableString(it) }
    .apply {
        spanStack.forEach {
            setSpan(
                BackgroundColorSpan(Color.YELLOW),
                it.first,
                it.second,
                SpannableString.SPAN_INCLUSIVE_INCLUSIVE
            )
        }
    }

textView.text = spannableString

<br/>

Result:

<tr>
<td><img src="https://i.stack.imgur.com/xDdRE.png" width="300"/></td>
</tr>

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  • 本文由 发表于 2020年7月22日 19:59:26
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