ByteBuffer discards trailing newline

Here is how I put a string to ByteBuffer

String message="Hello\n\n";
ByteBuffer bresult = ByteBuffer.allocate(message.getBytes().length);
bresult.put(message.getBytes());
bresult.flip();

When I convert bytebuffer to string to see the result \n\n is removed from the above string.
This how I convert ByteBuffer to String

print(new String(bresult.array()));

and the result is Hello without any line breaks.
You can see the result in the below screenshot from my log
[![enter image description here][1]][1]

but when I add spaces to hello string like message="Hello\n\n " the result is the below:
[![enter image description here][2]][2]
as you can see there are some line breaks under hello string.

I cannot reproduce the problem. The following:

import java.nio.ByteBuffer;

public class App {

  public static void main(String[] args) {
    String str = "Hello\n\n";

    ByteBuffer buf = ByteBuffer.allocate(str.getBytes().length);
    buf.put(str.getBytes());
    buf.flip();

    String str2 = new String(buf.array());

    System.out.println(str.equals(str2));
    System.out.println(str2.endsWith("\n\n"));
  }
}

Gives this output:

true
true

Which means the String created from the byte[] has all the same characters as the original String.

Some notes:

1. The use of ByteBuffer above is a roundabout way of doing str2 = new String(str.getBytes()). I used ByteBuffer since that's what you used in the question.

2. Be careful with String#getBytes() and String#<init>(byte[]). Both use the default platform encoding which may or may not cause problems. Consider specifying the encoding explicitly.

3. If I replace the test with System.out.print(str2) I get the following output:

   Hello
   
   

   That's "Hello" followed by two line breaks. If println was used instead then there would be three line breaks. Note that line breaks are not typically directly visible.