将动态的 JSON 键映射到一个类字段,使用 JPA。

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英文:

Map a dynamic json key to a class field using JPA

问题

我正在尝试将一个 JSON 对象映射到一个实体类(Entity class)。我的 JSON 如下所示:

{
    "availabilities": {
        "2020-07-14T00:00:00Z": "Not Available",
        "2020-08-14T00:00:00Z": "Not Available",
        "2020-06-14T00:00:00Z": "Not Available",
        "2020-05-14T00:00:00Z": "Not Available",
        "2020-00-14T00:00:00Z": "Not Available"
    }
}

我使用 Spring Data 创建了一个实体类:

@Entity
public class Availabilities {

    @Id
    @GeneratedValue(strategy = GenerationType.AUTO)
    private Long id;

    private String date;
    private String availability;

    public String getDate() {
        return date;
    }

    public void setDate(String date) {
        this.date = date;
    }

    public String getAvailability() {
        return availability;
    }

    public void setAvailability(String availability) {
        this.availability = availability;
    }
}

但我得到了以下错误:

com.fasterxml.jackson.databind.exc.UnrecognizedPropertyException: Unrecognized field "2020-07-14T00:00:00Z" (class org.abc.hotel.booking.model.Availabilities)

请帮助。

英文:

I am trying to map a json object to an Entity class. My Json is as follows:

    {
   
    "availabilities": {
    "2020-07-14T00:00:00Z": "Not Available",
    "2020-08-14T00:00:00Z": "Not Available",
    "2020-06-14T00:00:00Z": "Not Available",
    "2020-05-14T00:00:00Z": "Not Available",
    "2020-00-14T00:00:00Z": "Not Available"

      }
    }

I created a entity class using spring data :

@Entity
public class Availabilities {


@Id
@GeneratedValue(strategy = GenerationType.AUTO)
private Long id;


private String date;
private String availibility;



public String getDate() {
	return date;
}
public void setDate(String date) {
	this.date = date;
}
public String getAvailibility() {
	return availibility;
}
public void setAvailibility(String availibility) {
	this.availibility = availibility;
}

}

But i am getting the following error:

com.fasterxml.jackson.databind.exc.UnrecognizedPropertyException: Unrecognized field "2020- 
07-14T00:00:00Z" (class org.abc.hotel.booking.model.Availabilities)

Please help.

答案1

得分: 1

你的代码正在尝试按键值映射,这意味着你的变量是键。在你的情况下,JSON 应该如下工作:

// 映射到可用性
{
  "date": "2020-07-14T00:00:00Z",
  "availibility": "Not Available"
}

如果你想解析成列表 => https://stackoverflow.com/questions/44589381/how-to-convert-json-string-into-list-of-java-object

英文:

your code is trying map by key-value, that mean your variable is the key.
in your case. json look like this will work

// map to Availabilities
      {
        "date": "2020-07-14T00:00:00Z",
        "availibility": "Not Available",
      }

if you want to parse into a list => https://stackoverflow.com/questions/44589381/how-to-convert-json-string-into-list-of-java-object

huangapple
  • 本文由 发表于 2020年7月22日 09:56:35
  • 转载请务必保留本文链接:https://go.coder-hub.com/63025625.html
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