如何使用for循环创建一个二维数组,并分配线性值,增量为10?

huangapple go评论48阅读模式
英文:

How can I use a for loop to create a two dimensional array and assign linear values with an increment of 10?

问题

我想使用for循环创建一个二维数组,并希望以10的增量分配值。到目前为止,这是我的代码,但我没有得到想要的结果...

int rows = 3;
int columns = 3;

int[][] array = new int[rows][columns];

for (int i = 0; i < rows; i++) {
    for (int j = 0; j < columns; j++) {
        array[i][j] = j * 10;
        System.out.println(array[i][j]);
    }
}

这是我希望的输出:

0    30    60
10   40    70
20   50    80

Process finished with exit code 0

这是我一直得到的输出:

0
10
20
0
10
20
0
10
20

Process finished with exit code 0
英文:

I want to create a two dimensional array using a for loop and I want to assign values with an increment of 10. So far here is what I have and I am not getting the result I want...

package ~/TwoDimensionalArray;

import java.util.Scanner;

public class TwoDimensionalArray {

    public static void main(String[] args) {

        int rows = 3;
        int columns = 3;

        int[][] array = new int[rows][columns];

        for (int i = 0; i < rows; i++) {
            for (int j = 0; j < columns; j++) {
                array[i][j] = j * 10;
                System.out.println(array[i][j]);
            }
        }

    }

}

Here is what I want my output to be:

0	30	60
10	40	70
20	50	80

Process finished with exit code 0

Here is what I keep getting:

0
10
20
0
10
20
0
10
20

Process finished with exit code 0

答案1

得分: 1

  • 每个数字后不应该打印新行。
  • 只有在每行被打印后才应该打印新行,也就是在外部循环的每次迭代后。
  • 每个数字后面也应该打印一个制表符,以防止数字粘在一起。
  • 你可以使用公式 j * 10 * rows + i * 10 计算第 i 行第 j 列的数字,这样可以得到每个位置上的正确数字。
英文:
  • You should not print a new line after each number.
  • You should only print a new line after each row is printed, that is, after each iteration of the outer loop.
  • You should also print a tab character after each number so that the numbers don't stick together
  • You should calculate the number at row i column j using the formula j * 10 * rows + i * 10. This gives you the correct number at each position.
int rows = 3;
int columns = 3;

int[][] array = new int[rows][columns];

for (int i = 0; i < rows; i++) {
    for (int j = 0; j < columns; j++) {
        array[i][j] = j * 10 * rows + i * 10;
        System.out.print(array[i][j]); // "print" doesn't print a new line
        System.out.print("\t"); // print a tab!
    }
    System.out.println(); // print a new line here
}

答案2

得分: 0

以下是翻译好的部分:

public class TempTest {
    static final int ROW = 3;
    static final int COLUMN = 3;

    public static void main(String[] args) {
        int[][] array = new int[ROW][COLUMN];
        // 为数组分配值
        for (int i = 0; i < ROW; i++) {
            for (int j = 0; j < COLUMN; j++) {
                array[i][j] = 10 * (i + 3 * j);
            }
        }
        // 显示数组
        for (int i = 0; i < ROW; i++) {
            for (int j = 0; j < COLUMN; j++) {
                System.out.print(array[i][j]);
                System.out.print(' ');
            }
            System.out.println();
        }
    }
}

和结果将会是

0 30 60 
10 40 70 
20 50 80 

我认为您可能不熟悉printprintln之间的区别,后者会添加一个新行。尝试学更多关于JAVA的知识,祝好运!

英文:

maybe this is what u want

public class TempTest {
    static final int ROW = 3;
    static final int COLUMN = 3;

    public static void main(String[] args) {
        int[][] array = new int[ROW][COLUMN];
        // assign values to array
        for (int i = 0; i &lt; ROW; i++) {
            for (int j = 0; j &lt; COLUMN; j++) {
                array[i][j] = 10 * (i + 3 * j);
            }
        }
        // display array
        for (int i = 0; i &lt; ROW; i++) {
            for (int j = 0; j &lt; COLUMN; j++) {
                System.out.print(array[i][j]);
                System.out.print(&#39; &#39;);
            }
            System.out.println();
        }
    }
}

and the result will be

0 30 60 
10 40 70 
20 50 80 

I think u are not familiar with the difference between print and println, the latter one will add a new line. Try learn more about JAVA, good luck!

答案3

得分: 0

尝试这个。

int rows = 3;
int columns = 3;

int[][] array = new int[rows][columns];

for (int i = 0, v = 0; i < rows; i++) {
    for (int j = 0; j < columns; j++, v += 10) {
        array[i][j] = v;
        System.out.print(array[i][j] + "\t");
    }
    System.out.println();
}
英文:

Try this.

int rows = 3;
int columns = 3;

int[][] array = new int[rows][columns];

for (int i = 0, v = 0; i &lt; rows; i++) {
    for (int j = 0; j &lt; columns; j++, v += 10) {
        array[i][j] = v;
        System.out.print(array[i][j] + &quot;\t&quot;);
    }
    System.out.println();
}

huangapple
  • 本文由 发表于 2020年7月22日 08:21:57
  • 转载请务必保留本文链接:https://go.coder-hub.com/63024912.html
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