英文:
How to set an instance of the EventHandler interface as the action for a button
问题
我正在尝试通过将EventHandler<>接口的实例传递给其setOnAction()方法来设置按钮的操作，但是它不起作用。
Class 1:
public class Class1 {
private Class2 class2;
private Button buttonDelete = null;
private Button getButtonDelete() {
if (buttonDelete == null) {
buttonDelete = new Button("Delete");
buttonDelete.setOnAction(class2);
}
return buttonDelete;
}
}
Class 2:
public class Class2 implements EventHandler<ActionEvent> {
@Override
public void handle(ActionEvent event) {
// do something
}
}
英文:
I am trying to set the action of a button by passing an instance of the EventHandler<> interface to its setOnAction() method, however it is not working.
Class 1:
public class Class1 {
private Class2 class2;
private Button buttonDelete = null;
private Button getButtonDelete() {
if (buttonDelete == null) {
buttonDelete = new Button("Delete");
buttonDelete.setOnAction(class2);
}
return buttonDelete;
}
}
Class 2:
public class Class2 implements EventHandler<ActionEvent> {
@Override
public void handle(ActionEvent event) {
// do something
}
}
答案1
得分: 2
-
要调用构造函数：
new Class1(new Class2());当事件触发时，将自动调用handle方法。 -
长答案，使用匿名类更适合按钮事件处理，因此请了解匿名类和Lambda表达式，这是很好的学习。
英文:
- Short answer :
public Class1(Class2 class2){
this.class2 = class2;
}
To call the constructor : new Class1(new Class2()); the handle method will be called automatically when the event triggred.
- Long answer, using anonymous classes is better for button event handling so learn about anonymouse classes and lambda expressions, good learning.
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