英文:
regex for splitting a string while ignoring the brackets
问题
Sure, here's the translated content:
我想要通过空格字符来分割一个字符串，但忽略括号之间的空格。我使用的代码是：
String s = "hello (split this) string";
String reg = "(?<=([^\\(].*))( )(?=(.*[^\\)]))";
System.out.println(Arrays.toString(s.split(reg)));
我期望的输出是：
[hello , (split this) , string]
但我得到了这个错误：
Exception in thread "main" java.util.regex.PatternSyntaxException: Look-behind group does not have an obvious maximum length near index 12
(?<=([^(].))z(?=(.[^)]))
我需要一个正则表达式来获得期望的输出。所以，请有人帮忙。
英文:
I want to split a string with space-character but ignoring the space between two brackets.
The code i used is:
String s = "hello (split this) string";
String reg = "(?<=([^\\(].*))( )(?=(.*[^\\)]))";
System.out.println(Arrays.toString(s.split(reg));
My expected output is:
[hello , (split this) , string]
but i get this error
>Exception in thread "main" java.util.regex.PatternSyntaxException: Look-behind group does not have an obvious maximum length near index 12
(?<=([^(].))z(?=(.*[^)])) *
I need a regex to get the expected output.
So, somebody please help.
答案1
得分: 1
你可以使用以下正则表达式来实现你的需求：
[ ](?=[^\)]*?(?:\(|$))
以上正则表达式的解释：
>[ ] - 表示一个空格字符。
>
> (?=[^\)]*?(?:\(|$)) - 表示正向先行断言，断言括号()内的所有内容。
>
>(?:) - 表示一个非捕获组。
>
> | - 表示或操作。
>
> $ - 表示字符串的结尾。
你可以在这里找到上述正则表达式的演示。
在Java中的实现
import java.util.Arrays;
public class Main
{
public static void main(String[] args) {
String s = "hello (split this) string";
String reg = "[ ](?=[^\\)]*?(?:\\(|$))";
System.out.println(Arrays.toString(s.split(reg)));
}
}
// 输出: [hello, (split this), string]
你可以在这里找到上述实现。
英文:
You can use the below regex to achieve your requirement:
[ ](?=[^\)]*?(?:\(|$))
Explanation of the above regex:
>[ ] - Represents a space character.
>
> (?=[^\)]*?(?:\(|$)) - Represents a positive look-ahead asserting everything inside of ().
>
>(?:) - Represents a non-capturing group.
>
> | - Represents alternation.
>
> $ - Represents the end of the test String.
You can find the demo of the above regex in here.
IMPLEMENTATION IN JAVA
import java.util.Arrays;
public class Main
{
public static void main(String[] args) {
String s = "hello (split this) string";
String reg = "[ ](?=[^\\)]*?(?:\\(|$))";
System.out.println(Arrays.toString(s.split(reg)));
}
}
// output: [hello, (split this), string]
You can find the above implementation here.
答案2
得分: 1
尝试使用 "(?:[^ (]+|(?>\\([^()]*\\))|\\()+(?=[ ]|$)"
注意：
- 用于匹配所有元素，而不是进行分割
- 将匹配不平衡的括号，并在括号上使用原子组，如
( kk hh )
英文:
Try "(?:[^ (]+|(?>\\([^()]*\\))|\\()+(?=[ ]|$)"
notes
- use to match all elements instead of split
- will match unbalanced parens and use a atomic group on paren like
( kk hh )
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