如何同时修改多个EditText的输入,就像我只修改一个一样?

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英文:

How can I modify the input of multiple EditTexts at the same time, as I only modify one?

问题

我有多个 EditText,我希望在修改一个 EditText 的输入时,同时更改所有 EditText 的输入(它们都以十进制数作为输入)。

我将这些 EditText 存储在名为 'editTexts' 的数组中。

以下是我尝试过的代码:

// 为每个元素设置监听器
for (int i = 0; i < editTexts.length; i++) {
    final int finalI = i;
    editTexts[i].addTextChangedListener(new TextWatcher() {
        @Override
        public void beforeTextChanged(CharSequence s, int start, int count, int after) {

        }

        @Override
        public void onTextChanged(CharSequence s, int start, int before, int count) {
            // 如果当前正在编辑的 EditText 为空,则将其余所有 EditText 的输入设置为 '0.0'
            if (editTexts[finalI].getText().toString().trim().length() == 0) {
                for (EditText e : editTexts) {
                    if (e == editTexts[finalI])
                        continue;
                    e.setText("0.0");
                }
            } else {
                float no = Float.parseFloat(s.toString() + "");
                // 将所有其他 EditText 的输入设置为输入的小数乘以 2
                for (EditText e : editTexts) {
                    if (e == editTexts[finalI])
                        continue;
                    e.setText(no * 2 + "");
                }
            }
        }

        @Override
        public void afterTextChanged(Editable s) {

        }
    });
}

在这种情况下,乘法系数只是一个示例,它不总是为 2。我只是用它进行测试。

出现某种原因,当我更改输入值时,应用程序会冻结。

需要帮助吗?谢谢!

英文:

I have multiple EditTexts and I want to change the input of all of them at the same time, as I modify only one.(all of them take decimal numbers as input)

I stored the EditTexts in an array named 'editTexts'.

Here's what I tried

//Set the listener for each element
for (int i=0; i&lt;editTexts.length; i++) {
        final int finalI = i;
        editTexts[i].addTextChangedListener(new TextWatcher() {
            @Override
            public void beforeTextChanged(CharSequence s, int start, int count, int after) {

            }

            @Override
            public void onTextChanged(CharSequence s, int start, int before, int count) {
//if the editText which is currently edited is empty, set the input for all the rest to be &#39;0.0&#39;
                if (editTexts[finalI].getText().toString().trim().length() == 0) {
                    for(EditText e : editTexts) {
                        if (e == editTexts[finalI])
                            continue;
                        e.setText(&quot;0.0&quot;);
                    }
                } else {
                    float no = Float.parseFloat(s.toString() + &quot;&quot;);
//Set the input of all the other editTexts to be the decimal number entered, multiplied by 2
                    for(EditText e : editTexts){
                        if(e == editTexts[finalI])
                            continue;
                        e.setText(no*2+&quot;&quot;);
                    }
                }
            }

            @Override
            public void afterTextChanged(Editable s) {

            }
        })
    }

In this case the multiplication coefficient is just an example, it's not always gonna be 2. I used it just to test it out.

For some reason, when I change the input value, the app freezes.

Any help? Thanks!

答案1

得分: 2

使用LiveData来存储您的用户输入值。
一旦它的值发生变化,您可以将值设置给每个EditText。我认为这是一种简单的实现方式。

英文:

Use LiveData to store your user input values.
Once it's value changes you can set value to each EditText. I think it is an easy way to implement.

答案2

得分: 2

// et_x1、et_x2和et_x3是EditText的ID
// 将所有EditText的inputType设置为numberDecimal

EditText editText1 = findViewById(R.id.et_x1);
final EditText editText2 = findViewById(R.id.et_x2);
final EditText editText3 = findViewById(R.id.et_x3);

editText1.addTextChangedListener(new TextWatcher() {
    @Override
    public void beforeTextChanged(CharSequence s, int start, int count, int after) {

    }

    @Override
    public void onTextChanged(CharSequence s, int start, int before, int count) {
        String value = s.toString();
        double x;
        if (!value.equals("")) {
            x = Double.parseDouble(value);
        } else {
            x = 0.0;
        }
        editText2.setText(Editable.Factory.getInstance().newEditable((String.valueOf(Math.pow(x, 2)))));
        editText3.setText(
                Editable.Factory.getInstance().newEditable((String.valueOf(Math.pow(x, 3)))));
    }

    @Override
    public void afterTextChanged(Editable s) {

    }
});

希望对你有所帮助!

英文:

Try it like this:

// et_x1, et_x2 and et_x3 are ids of EditTexts
//set inputType for all EditTexts as numberDecimal

EditText editText1 = findViewById(R.id.et_x1);
final EditText editText2 = findViewById(R.id.et_x2);
final EditText editText3 = findViewById(R.id.et_x3);


editText1.addTextChangedListener(new TextWatcher() {
    @Override
    public void beforeTextChanged(CharSequence s, int start, int count, int after) {

    }

    @Override
    public void onTextChanged(CharSequence s, int start, int before, int count) {
        String value = s.toString();
        double x;
        if (!value.equals(&quot;&quot;)) {
            x = Double.parseDouble(value);
        } else {
            x = 0.0;
        }
        editText2.setText(Editable.Factory.getInstance().newEditable((String.valueOf(Math.pow(x, 2)))));
        editText3.setText(
                Editable.Factory.getInstance().newEditable((String.valueOf(Math.pow(x, 3)))));
    }

    @Override
    public void afterTextChanged(Editable s) {

    }
});

Hope it helps you!

huangapple
  • 本文由 发表于 2020年5月30日 21:53:46
  • 转载请务必保留本文链接:https://go.coder-hub.com/62103423.html
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