如何同时修改多个EditText的输入，就像我只修改一个一样？

huangapple
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英文:

How can I modify the input of multiple EditTexts at the same time, as I only modify one?

问题

我有多个 EditText，我希望在修改一个 EditText 的输入时，同时更改所有 EditText 的输入（它们都以十进制数作为输入）。

我将这些 EditText 存储在名为 'editTexts' 的数组中。

以下是我尝试过的代码：

  1. // 为每个元素设置监听器
  2. for (int i = 0; i < editTexts.length; i++) {
  3.     final int finalI = i;
  4.     editTexts[i].addTextChangedListener(new TextWatcher() {
  5.         @Override
  6.         public void beforeTextChanged(CharSequence s, int start, int count, int after) {
  8.         }
  10.         @Override
  11.         public void onTextChanged(CharSequence s, int start, int before, int count) {
  12.             // 如果当前正在编辑的 EditText 为空，则将其余所有 EditText 的输入设置为 '0.0'
  13.             if (editTexts[finalI].getText().toString().trim().length() == 0) {
  14.                 for (EditText e : editTexts) {
  15.                     if (e == editTexts[finalI])
  16.                         continue;
  17.                     e.setText("0.0");
  18.                 }
  19.             } else {
  20.                 float no = Float.parseFloat(s.toString() + "");
  21.                 // 将所有其他 EditText 的输入设置为输入的小数乘以 2
  22.                 for (EditText e : editTexts) {
  23.                     if (e == editTexts[finalI])
  24.                         continue;
  25.                     e.setText(no * 2 + "");
  26.                 }
  27.             }
  28.         }
  30.         @Override
  31.         public void afterTextChanged(Editable s) {
  33.         }
  34.     });
  35. }

在这种情况下，乘法系数只是一个示例，它不总是为 2。我只是用它进行测试。

出现某种原因，当我更改输入值时，应用程序会冻结。

需要帮助吗？谢谢！

英文:

I have multiple EditTexts and I want to change the input of all of them at the same time, as I modify only one.(all of them take decimal numbers as input)

I stored the EditTexts in an array named 'editTexts'.

Here's what I tried

  1. //Set the listener for each element
  2. for (int i=0; i&lt;editTexts.length; i++) {
  3.         final int finalI = i;
  4.         editTexts[i].addTextChangedListener(new TextWatcher() {
  5.             @Override
  6.             public void beforeTextChanged(CharSequence s, int start, int count, int after) {
  8.             }
  10.             @Override
  11.             public void onTextChanged(CharSequence s, int start, int before, int count) {
  12. //if the editText which is currently edited is empty, set the input for all the rest to be &#39;0.0&#39;
  13.                 if (editTexts[finalI].getText().toString().trim().length() == 0) {
  14.                     for(EditText e : editTexts) {
  15.                         if (e == editTexts[finalI])
  16.                             continue;
  17.                         e.setText(&quot;0.0&quot;);
  18.                     }
  19.                 } else {
  20.                     float no = Float.parseFloat(s.toString() + &quot;&quot;);
  21. //Set the input of all the other editTexts to be the decimal number entered, multiplied by 2
  22.                     for(EditText e : editTexts){
  23.                         if(e == editTexts[finalI])
  24.                             continue;
  25.                         e.setText(no*2+&quot;&quot;);
  26.                     }
  27.                 }
  28.             }
  30.             @Override
  31.             public void afterTextChanged(Editable s) {
  33.             }
  34.         })
  35.     }

In this case the multiplication coefficient is just an example, it's not always gonna be 2. I used it just to test it out.

For some reason, when I change the input value, the app freezes.

Any help? Thanks!

答案1

得分: 2

使用LiveData来存储您的用户输入值。
一旦它的值发生变化，您可以将值设置给每个EditText。我认为这是一种简单的实现方式。

英文:

Use LiveData to store your user input values.
Once it's value changes you can set value to each EditText. I think it is an easy way to implement.

答案2

得分: 2

  1. // et_x1、et_x2和et_x3是EditText的ID
  2. // 将所有EditText的inputType设置为numberDecimal
  4. EditText editText1 = findViewById(R.id.et_x1);
  5. final EditText editText2 = findViewById(R.id.et_x2);
  6. final EditText editText3 = findViewById(R.id.et_x3);
  8. editText1.addTextChangedListener(new TextWatcher() {
  9.     @Override
  10.     public void beforeTextChanged(CharSequence s, int start, int count, int after) {
  12.     }
  14.     @Override
  15.     public void onTextChanged(CharSequence s, int start, int before, int count) {
  16.         String value = s.toString();
  17.         double x;
  18.         if (!value.equals("")) {
  19.             x = Double.parseDouble(value);
  20.         } else {
  21.             x = 0.0;
  22.         }
  23.         editText2.setText(Editable.Factory.getInstance().newEditable((String.valueOf(Math.pow(x, 2)))));
  24.         editText3.setText(
  25.                 Editable.Factory.getInstance().newEditable((String.valueOf(Math.pow(x, 3)))));
  26.     }
  28.     @Override
  29.     public void afterTextChanged(Editable s) {
  31.     }
  32. });

希望对你有所帮助！

英文:

Try it like this:

  1. // et_x1, et_x2 and et_x3 are ids of EditTexts
  2. //set inputType for all EditTexts as numberDecimal
  4. EditText editText1 = findViewById(R.id.et_x1);
  5. final EditText editText2 = findViewById(R.id.et_x2);
  6. final EditText editText3 = findViewById(R.id.et_x3);
  9. editText1.addTextChangedListener(new TextWatcher() {
  10.     @Override
  11.     public void beforeTextChanged(CharSequence s, int start, int count, int after) {
  13.     }
  15.     @Override
  16.     public void onTextChanged(CharSequence s, int start, int before, int count) {
  17.         String value = s.toString();
  18.         double x;
  19.         if (!value.equals(&quot;&quot;)) {
  20.             x = Double.parseDouble(value);
  21.         } else {
  22.             x = 0.0;
  23.         }
  24.         editText2.setText(Editable.Factory.getInstance().newEditable((String.valueOf(Math.pow(x, 2)))));
  25.         editText3.setText(
  26.                 Editable.Factory.getInstance().newEditable((String.valueOf(Math.pow(x, 3)))));
  27.     }
  29.     @Override
  30.     public void afterTextChanged(Editable s) {
  32.     }
  33. });

Hope it helps you!

huangapple
  • 本文由 发表于 2020年5月30日 21:53:46
  • 转载请务必保留本文链接：https://go.coder-hub.com/62103423.html
  • android
  • android-edittext
  • java
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