How to create random numbers a specific number of times?

How can i create a random number a specific numbers of time?

public class Feld  {
    public static void main(String[] args) {
		double k = (int)(Math.random()*1000001);
        int n = 1000000;
        int arr[] = new int[n];
        int i = 0;
        for(i = 0;i<n;i++){
            arr[i] = i;
        }
        boolean found = false;
        i=0;
        while (i < arr.length) {
            if (arr[i] == k) {
                found = true;
                break;
            }
			i++;
        }
        if (found) {
			i++;
            System.out.println(i);
        } 
		else {
            System.out.println((arr.length + 1));
        }
    }
}

My problem is, that if i put k into a loop to create it more than one time i'll get an error at:

if (arr[i] == k)

!!I just found out that i made a mistake explaining my problem. The array should be filled with values from 0-1.000.000 and i am supposed to print out the position of a random generated number for a specific amount of times.

If you want to have an array full of random numbers, I suggest using the following:

int n = 1000000;
int arr[] = new int[n];
for(int i = 0; i < n; i++){
    arr[i] = (int)(Math.random() * 1000001);
}

That will work and you don't even need the variable k.

Edit:

If you want to print at what position you find a specific value (for example x = 543), you can use the following code:

int x = 543;
int n = 1000000;
int arr[] = new int[n];
for(int i = 0; i < n; i++){
    arr[i] = (int)(Math.random() * 1000001);
    if(arr[i] == x) {
        System.out.println(i);
        break;
    }
}

Edit2

One possible solution to your new problem looks like this:

public class Feld  {
    public static void main(String[] args) {
        int n = 1000000;
        int arr[] = new int[n];
        int i = 0;
        for(i = 0; i < n; i++){
            arr[i] = i; //Filling array with values 0-1000000
        }
        int number = 20;	//Print out position of a random generated number a specific amount of times
        int randomNumber = (int)(Math.random()*1000001); //The random number
        
        for(int j = 0; j < number; j++) { //Find number for a specific amount of times 
        	for(int k = 0; k < arr.length; k++) { //Find number in array
        		if(arr[k] == randomNumber) { 
        			System.out.println(arr[k]); //Print
        			break; //Number found, don't have to search anymore
        		}
        	}
        }
    }
}

I would write a method that returns an array of random numbers and takes an int argument that defines the length of the array.

One possible solution is this:

public static int[] createRandomArray(int length) {
	// create an array of the given length
	int[] result = new int[length];
	// and use a single for loop that puts random int values into every index
	for (int i = 0; i < result.length; i++) {
		result[i] = ThreadLocalRandom.current().nextInt();
	}
	// then simply return the result
	return result;
}

Try it as follows

public static void main(String[] args) {
	// super primitive time measurement:
	// take the moment in time before calling the method
	Instant start = Instant.now();
	// then call the method
	int[] array = createRandomArray(1000000);
	// and take the moment in time after the method returned
	Instant end = Instant.now();
	// then calculate the duration
	Duration duration = Duration.between(start, end);
	// and print the duration in milliseconds
	System.out.printf("Array creation took %d milliseconds\n", duration.toMillis());
}

The result is the following output on my system:

Array creation took 10 milliseconds