英文:
Is there any way I can output the variable name instead of the value? [JAVA]
问题
例如，我有一个整数变量的列表
int CLUTCH_CASE = 8;
int CS20 = 6;
int DANGER_ZONE_CASE = 6;
int TOTAL_CASE = 0;
我有一个数组：
int CaseValue[] = {CS20, CLUTCH_CASE, DANGER_ZONE_CASE};
然后我输出总箱数的值，结果将会是：
for (int counter=0;counter<CaseValue.length;counter++) {
TOTAL_CASE += CaseValue
}
System.out.println("你有 "+CaseValue.length+" 个CSGO箱子");
System.out.println("你总共有 "+TOTAL_CASE+" 个CSGO箱子:");
输出：
你有 3 个CSGO箱子
你总共有 20 个CSGO箱子:
然而我还想要输出名称。示例：（在这个示例中，CASENAME只是占位符。我想使用CaseValue[].NAME，即使它不存在，因为这只是一个示例）
for (int counter2=0;counter2<CaseValue.length;counter2++) {
System.out.println(CASENAME+": "+CaseValue[counter2]);
}
我期望的输出是：
CLUTCH_CASE: 8
CS20: 6
DANGER_ZONE_CASE: 6
有没有办法输出整数变量的名称呢？
英文:
for example, I have a list of integer variables
int CLUTCH_CASE = 8;int CS20 = 6;int DANGER_ZONE_CASE = 6;int TOTAL_CASE = 0;
I have an array:
int CaseValue[] = {CS20, CLUTCH_CASE, DANGER_ZONE_CASE};
and I output the value of total cases, which is going to be:
for (int counter=0;counter<CaseValue.length;counter++) {TOTAL_CASE += CaseValue;0+网站访问量}System.out.println("You have "+CaseValue.length+" CSGO Cases");System.out.println("You have a total of "+TOTAL_CASE+" CSGO Cases:");
Output:
You have 3 CSGO CasesYou have a total of 20 CSGO Cases:
yet I also want to output the name.
Example:
(CASENAME are just placeholders for this example. I wanted to use CaseValue[].NAME even that does not exist since it's an example)
for (int counter2=0;counter2<CaseValue.length;counter2++) {System.out.println(CASENAME+": "+CaseValue[counter2]);}
My expected and wanted output to be:
CLUTCH_CASE: 8CS20: 6DANGER_ZONE_CASE: 6
Is there any way to output the name of the integer variable?
答案1
得分: 2
在Java中没有命令可以访问变量名。
你可以使用一个映射（就像其他答案中所述），但我也想提供一个简单的可能性，这个可能性不需要Java的高级特性。
你可以这样做：
String[] caseName = {"CS20", "CLUTCH_CASE", "DANGER_ZONE_CASE"};
之后你可以进行如下操作：
for (int i=0; i<CaseValue.length; i++) {System.out.println(caseName[i] + ": " + CaseValue[i]);}
英文:
There is no command in Java to access the variable name.
You could use a map (like stated in other answers), but I'd also like to present a simple possibility that is possible without advanced features of Java.
What you could do is the following:
String[] caseName = {"CS20", "CLUTCH_CASE", "DANGER_ZONE_CASE"};
After that you can do:
for (int i=0; i<CaseValue.length; i++) {System.out.println(caseName[i] + ": " + CaseValue[i]);}
答案2
得分: 0
使用 Map。
Map<String, Integer> ma = new Hashmap();for (int counter=0; counter<CaseValue.length; counter++) {TOTAL_CASE += CaseValue[counter];ma.put(<你的键>, <你的值>);}
我仍然不完全理解你的代码。因此无法为你提供完整的工作代码片段。但是我已经添加了一个片段，展示了如何可能使用一个 Map。将键的名称作为你想要的名称，并将其对应的值存储在该键的映射中。
英文:
Use a Map.
Map<String, Integer> ma = new Hashmap()for (int counter=0;counter<CaseValue.length;counter++) {TOTAL_CASE += CaseValue;0+网站访问量ma.put(<your_key>, <your_value>)}
I still dont understand your code completely. So cannot give you a full working snippet. I have however added a snippet on how you could possibly use a map. Store the key as the name that you want and its corresponding value in that key of the map.
答案3
得分: 0
你需要使用 java.lang.Class 及其 getFields() 方法来返回一个 java.lang.reflect Field[] 类对象的数组。
以下将给你一个想法，如何使用 API 文档中更适合的一组方法来设计这个过程，可以使用 List 或 Set，并使用 contains() 方法，这样你可以将它放入一个类中，在程序中需要的时候进行调用。
import java.lang.Class;import java.lang.reflect.*;Field[] varFset = ((java.lang.Class)this).getFields();// 在这里进行对数组的名称比较处理代码String varname = varFset[x].getName();
英文:
You need to use java.lang.Class and its getFields() method to return an array of java.lang.reflect Field[] class object
Below will give you an idea of how, go take a look in the API docs for a better more suitable set of methods to design the process with a List or Set to use contains() method so you can put it in a class and call when you want in a program.
import java.lang.Class;import java.lang.reflect.*;Field[] varFset = ((java.lang.Class)this).getFields();// compare names processing code over the array hereString varname = varFset[x].getName();
答案4
得分: -1
你可以使用 HashMap。
enum CaseType {CLUTCH_CASE,CS20,DANGER_ZONE_CASE;}Map<CaseType, Integer> map = new HashMap<>(3);map.put(CaseType.CLUTCH_CASE, 8);map.put(CaseType.CS20, 6);map.put(CaseType.DANGER_ZONE_CASE, 6);map.forEach((key, value) -> System.out.println(key.name() + ": " + value));
英文:
You could use a HashMap.
enum CaseType {CLUTCH_CASE,CS20,DANGER_ZONE_CASE;}Map<CaseType, Integer> map = new HashMap<>(3);map.put(CaseType.CLUTCH_CASE, 8);map.put(CaseType.CS20, 6);map.put(CaseType.DANGER_ZONE_CASE, 6);map.forEach((key, value) -> System.out.println(key.name() + ": " + value));
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