英文:
Splitting a string using a next line regex followed by a digit (JAVA)
问题
我有以下需要根据空格、逗号和换行符进行分割的字符串。
示例字符串：“./homework2 3,phone3,desc3,brand4\n4,phone4,desc4,brand4\n5,phone5,desc5,brand5”。
我正在使用以下分割函数：.split(""[,\\s+\\n+]");，但是我无法获得所需的输出。程序继续将brand4\n4读作一个子字符串。
希望能得到帮助。
英文:
I have the following string which I need to split on space, commas, and next line character.
Sample string: "./homework2 3,phone3,desc3,brand4\n4,phone4,desc4,brand4\n5,phone5,desc5,brand5"
I am using split function as: .split("[,\\s+\\n+]"); but I am unable to get the required out put. The program keeps reading brand4\n4 as one substring.
Help would be appreciated.
答案1
得分: 0
尝试这样做，它应该按你想要的方式工作：
.split(" |,|\\n");
这将在空格 (" "), 逗号或换行符处分割字符串。如果需要，使用或运算符添加更多条目。
英文:
Try this, it should work the way you want:
.split(" |,|\\n");
This splits the string at a space (" "), a comma, or a next line character. Use the or operator to add more entries if needed.
答案2
得分: 0
尝试以下代码：
String str = "./homework2 3,phone3,desc3,brand4\\n4,phone4,desc4,brand4\\n5,phone5,desc5,brand5";String[] arrOfStr = str.split("[\\s\\n,]+");for (String a : arrOfStr)System.out.println(a);
输出：
./homework23phone3desc3brand4\n4phone4desc4brand4\n5phone5desc5brand5
编辑：
我在这个网站上找到了这个函数：链接在这里
for (int i = 0 ; i < arrOfStr.length ; i++) { //YOUR LOOP !!!splitString(arrOfStr[i]);}
static void splitString(String str){StringBuffer alpha = new StringBuffer(),num = new StringBuffer(), special = new StringBuffer();for (int i=0; i<str.length(); i++){if (Character.isDigit(str.charAt(i)))num.append(str.charAt(i));else if(Character.isAlphabetic(str.charAt(i)))alpha.append(str.charAt(i));elsespecial.append(str.charAt(i));}System.out.println(alpha);System.out.println(num);}
将这两个函数组合起来，你会得到：
homework23phone3desc3brandn44phone4desc4brandn45phone5desc5brand5
你可以将这些值存储在另一个数组中，或者选择其他方式。
英文:
Try this code :
String str = "./homework2 3,phone3,desc3,brand4\\n4,phone4,desc4,brand4\\n5,phone5,desc5,brand5";String[] arrOfStr = str.split("[\\s\\n,]+");for (String a : arrOfStr)System.out.println(a);}}
Out put :
./homework23phone3desc3brand4\n4phone4desc4brand4\n5phone5desc5brand5
EDIT :
I found this function in the site : Link Here
for (int i = 0 ; i < arrOfStr.length ; i++) { //YOUR LOOP !!!splitString(arrOfStr[i]);}}static void splitString(String str){StringBuffer alpha = new StringBuffer(),num = new StringBuffer(), special = new StringBuffer();for (int i=0; i<str.length(); i++){if (Character.isDigit(str.charAt(i)))num.append(str.charAt(i));else if(Character.isAlphabetic(str.charAt(i)))alpha.append(str.charAt(i));elsespecial.append(str.charAt(i));}System.out.println(alpha);System.out.println(num);}}
Combine the two functions and you get:
homework23phone3desc3brandn44phone4desc4brandn45phone5desc5brand5
You can store the values in another array, or whatever you choose.
答案3
得分: 0
请查看以下链接以验证正则表达式：
https://regex101.com/r/2ZkRBp/1/
答案4
得分: 0
代替使用 \s+ 和 \n+，您可以使用一个常见的量词。下面显示了相同的内容：
String s = "./homework2 3,phone3,desc3,brand4\n4,phone4,desc4,brand4\n5,phone5,desc5,brand5";String[] s1 = s.split("[,\\s\\n]+");for (String s2 : s1) {System.out.println(s2);}
因为它导致了：
./homework23phone3desc3brand44phone4desc4brand45phone5desc5brand5
如果您有任何其他问题，欢迎提出。
英文:
Instead of using \s+ and \n+ you could use a common quantifier. The below depicts the same
String s = "./homework2 3,phone3,desc3,brand4\n4,phone4,desc4,brand4\n5,phone5,desc5,brand5";String[]s1 = s.split("[,\\s\\n]+");for(String s2:s1) {System.out.println(s2);}
As it leads to
./homework23phone3desc3brand44phone4desc4brand45phone5desc5brand5
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