英文:
Why is not operator giving different result but using = giving correct answer
问题
static int count = 0;public static void main(String[] args) {Scanner sc = new Scanner(System.in);count = 0;int n = sc.nextInt();int arr[][] = new int[n][n];for (int i = 0; i < n; i++) {for (int j = 0; j < n; j++) {arr[i][j] = sc.nextInt();}}for (int i = 0; i < n ; i++) {row(arr, n, i);column(arr, n, i);}System.out.println(count);for (int i = 0; i < n; i++) {for (int j = 0; j < n; j++) {System.out.print(arr[i][j] + " ");}}}static void row(int arr[][], int n, int row) {int x, y, min, yHold = 0;for (x = 0; x < n; x++) {boolean yes = false;min = arr[row][x];for (y = row; y < n; y++) {if (arr[y][x] < min) {min = arr[y][x];yHold = y;yes = !yes; // Here is the change you mentioned}}if (yes) {int temp = arr[row][x];arr[row][x] = min;arr[yHold][x] = temp;count++;}}
如果我将yes=true替换为yes=!yes，输出会变得不同。请帮忙，我似乎无法理解这个问题。函数row所处理的问题部分是：
如果我们在第i行，则必须逐列从0到n−1处理该行。对于任何第j列，将A[i][j]与索引为i到n−1的行中在第j列上存在的所有元素的最小值进行交换。
英文:
static int count = 0;public static void main(String[] args) {Scanner sc = new Scanner(System.in);count = 0;int n = sc.nextInt();int arr[][] = new int[n][n];for (int i = 0; i < n; i++) {for (int j = 0; j < n; j++) {arr[i][j] = sc.nextInt();}}for (int i = 0; i < n ; i++) {row(arr, n, i);column(arr, n, i);}System.out.println(count);for (int i = 0; i < n; i++) {for (int j = 0; j < n; j++) {System.out.print(arr[i][j] + " ");}}}static void row(int arr[][], int n, int row) {int x, y, min, yHold = 0;for (x = 0; x < n; x++) {boolean yes = false;min = arr[row][x];for (y = row; y < n; y++) {if (arr[y][x] < min) {min = arr[y][x];yHold = y;yes = true;}}if (yes) {int temp = arr[row][x];arr[row][x] = min;arr[yHold][x] = temp;count++;}}
If I replace yes=true with yes=!yes, the output becomes different. Please help, can't seem to figure it out.
The part of the problem the function row is taking are of is:
> If we are at ith row, then we have to work with each column at a time
> from 0 to n−1 of this row. For any jth column, swap A[i][j] with the
> minimum of all the elements which are present in a column with index j
> and rows from indices i to n−1.
答案1
得分: 3
问题在于该语句可以被执行多次。在 yes = true 的情况下，结果将永远是 yes 变为 true。但是使用 yes = !yes，结果是 yes 会在 true 和 false 之间不断翻转。
英文:
The problem is that the statement can be executed multiple times. In the case of yes = true, the result will always be that yes becomes true. But with yes = !yes, the result is that yes will flip flop between true and false.
答案2
得分: 3
以下是您要翻译的内容：
当您说 yes = true 时，它将始终为真。但是当您说 yes = !yes 时，它会在真和假之间来回切换。
boolean yes = true;for (int i = i < 10; i++) {System.out.println(yes);yes = !yes;}
输出：
真假真假真假真假真假
英文:
When you say yes = true, it is always going to be true. But when you say, yes = !yes it will flip back and forth between true and false.
boolean yes = true;for (int i = i < 10; i++) {System.out.println(yes);yes =! yes;}
prints
truefalsetruefalsetruefalsetruefalsetruefalse</details>
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