英文:
How to replace an unknown-substring in a string with specific pattern using Java code?
问题
import java.util.regex.Matcher;import java.util.regex.Pattern;public class StringReplacement {public static void main(String[] args) {String string1 = "text1 src=\"arbitrary_string_1\" text2";String string2 = "text3 src=\"arbitrary_string_2\" text4";String replacement = "stackoverflow";String updatedString1 = replaceArbitraryString(string1, replacement);String updatedString2 = replaceArbitraryString(string2, replacement);System.out.println(updatedString1);System.out.println(updatedString2);}public static String replaceArbitraryString(String input, String replacement) {String pattern = "src=\"[^\"]+\"";Pattern regexPattern = Pattern.compile(pattern);Matcher matcher = regexPattern.matcher(input);if (matcher.find()) {String found = matcher.group();return input.replace(found, "src=\"" + replacement + "\"");}return input;}}
这段代码可以用来替换类似于 "string1 src="arbitrary string" string2" 格式的字符串中的 "arbitrary string" 部分为特定的字符串（例如 "stackoverflow"）。
英文:
I deal with many strings whose pattern is similar "string1 src="arbitrary string" string2" and I want to replace the "arbitrary string" with specific string (let's say "stackoverflow")
using Java code.
For example, change these strings:
String string1 = "text1 src="arbitrary_string_1" text2"String string2 = "text3 src="arbitrary_string_2" text4"
to:
string1 = "text1 src="stackoverflow" text2"string2 = "text3 src="stackoverflow" text4"
I tried several codes using substring() function like:
String string1 = "text1 src=\"arbitrary string\" text2" \\declaration of string1Sting newString = string1.substring(0,indexOf("src")) + "src=\"stackoverflow\"" \\trying of the replacement
but it clearly cuts the ending of the string "code".
I also thought about the option of replacement using the pattern of the strings I deal with, but I dont know how to do that..
Any help would be greatly appreciated!
答案1
得分: 0
看一下这个：
public static String replaceAbitrary(String input, String replacement) {// 从开头到第一个 " 的部分。如果你不想在结果中包含 "，可以移除 +1String start = input.substring(0, input.indexOf('\"') + 1);// 从最后一个 " 开始的部分。如果你不想在结果中包含 "，添加一个 +1String end = input.substring(input.lastIndexOf('\"'));// 把它们组合起来return start + replacement + end;}public static void main(String[] args) throws IOException {// 输入部分。注意，这个系统甚至允许任意字符串中包含引号。String input = "text1 src=\"arbitrary \"string\"\" text2";// 要替换成的字符串。String replacement = "stackoverflow";System.out.println(replaceAbitrary(input, replacement));}
这会输出 text1 src="stackoverflow" text2。如果你不想包含引号，按照代码内的指示操作。
英文:
Take a look at this:
public static String replaceAbitrary(String input, String replacement) {// The input up to the first ". If you don't want to include the " in you// result, remove the +1String start = input.substring(0, input.indexOf('"') + 1);// The input starting from the last ". If you don't want to include the ", add a// +1String end = input.substring(input.lastIndexOf('"'));// Put it all togetherreturn start + replacement + end;}public static void main(String[] args) throws IOException {// The input. Note that this system even allows quotation marks inside the// arbitrary string.String input = "text1 src=\"arbitrary \"string\"\" text2";// The string to put instead of the arbitrary one.String replacement = "stackoverflow";System.out.println(replaceAbitrary(input, replacement));}
This outputs text1 src="stackoverflow" text2. If you don't want the quotation marks included, follow the instructions inside the code.
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