英文:
How to count syllables in word using Java?
问题
以下是翻译好的内容：
我正在开发一个学生项目，需要编写一个函数来计算单词中的音节。函数的形式类似于 long countSyllables(String word)。
如何使用Java计算单词中的音节？有什么建议吗？
提供的规则如下：
-
要计算音节数，应该使用字母 a、e、i、o、u、y 作为元音字母。
-
统计单词中元音字母的数量。
-
不要计算双元音字母（例如，“rain” 有2个元音字母，但只有1个音节）。
-
如果单词的最后一个字母是 'e'，不要将其视为元音字母（例如，“side” 是1个音节）。
-
如果最终发现单词中不包含元音字母，则将此单词视为1个音节。
我已经编写了这个函数，但我认为它不是最优的。所以我想看到其他可能的解决方案。如果有的话。
任务的完整描述：https://hyperskill.org/projects/39/stages/208/implement
当前的实现：
public static int countSyllables(final String word) {
return max(1, word.toLowerCase()
.replaceAll("e$", "")
.replaceAll("[aeiouy]{2}", "a")
.replaceAll("[^aeiouy]", "")
.length());
}
英文:
I am developing a student project and need to write a function to count syllables in word. The function is like long countSyllables(String word).
How to count syllables in word using Java? Any suggestions?
The provided rules are:
-
To count the number of syllables you should use letters a, e, i, o, u, y as vowels.
-
Count the number of vowels in the word.
-
Do not count double-vowels (for example, "rain" has 2 vowels but is only 1 syllable)
-
If the last letter in the word is 'e' do not count it as a vowel (for example, "side" is 1 syllable)
-
If at the end it turns out that the word contains 0 vowels, then consider this word as 1-syllable.
I had already write the function but I think it is not optimal. So I just would like to see other possible solutions. If any.
Full description for the task: https://hyperskill.org/projects/39/stages/208/implement
Current implementation:
public static int countSyllables(final String word) {
return max(1, word.toLowerCase()
.replaceAll("e$", "")
.replaceAll("[aeiouy]{2}", "a")
.replaceAll("[^aeiouy]", "")
.length());
}
答案1
得分: 1
public static int countSyllables(final String word) {
return max(1, word.toLowerCase()
//在以“e”结尾的单词中，将“e”替换为空字符串
.replaceAll("e$", "") //例如 base=bas
//当连续两个元音字母在一起时，
//用字母“a”替换它们
.replaceAll("[aeiouy]{2}", "a") //例如 you == au,
//beautiful==bautiful
//同样，当连续两个元音字母在一起时，
//用字母“a”替换它们
.replaceAll("[aeiouy]{2}", "a") //例如 au == a,
//bautiful==batiful
//将不是aeiouy的任何字符替换为空字符串
.replaceAll("[^aeiouy]", "") //例如 batiful==aiu,
//a == a
.length() //aiu == 3 音节, a == 1 音节
);
}
英文:
public static int countSyllables(final String word) {
return max(1, word.toLowerCase()
//in words that end with "e" replace
//"e" with ""
.replaceAll("e$", "") //e.g base=bas
//when two vowels appear together,
//replace them with "a"
.replaceAll("[aeiouy]{2}", "a") //e.g you == au,
//beautiful==bautiful
//again, when two vowels appear together,
//replace them with "a"
.replaceAll("[aeiouy]{2}", "a") //e.g au == a,
//bautiful==batiful
//replace any character that isn't aeiouy with ""
.replaceAll("[^aeiouy]", "") //e.g, batiful==aiu,
//a == a
.length() //aiu == 3 syllables, a == 1 syllable
);
}
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