英文:
Data processing on spark using java
问题
我有一个 DataSet。+-------------------+| 日期 |+-------------------+|1970-01-01 06:00:00|+-------------------+我想要只提取小时和分钟。列 "日期" 是时间戳类型。我尝试了以下代码：String format = "HH:mm";df.withColumn("时:分",unix_timestamp(col("日期"),format)).show(100);但对我来说没有起作用。谢谢。
英文:
I have a DataSet.
+-------------------+| Date |+-------------------+|1970-01-01 06:00:00|+-------------------+
I want to take only the hour and the minute.The column Date is on timestamp.
I tried the following code :
String format = "HH:mm";df.withColumn("hour:minute",unix_timestamp(col("Date"),format)).show(100);
But doesn't work for me .
Thank you .
答案1
得分: 1
unix_timestamp 函数将时间戳转换为 epoch/unix 时间。
- 使用
date_format、from_unixtime(unix_timestamp())函数之一来提取hour:minute。
示例：
df.withColumn("hour:minute", date_format(col("Date"), "HH:mm")).show()df.withColumn("hour:minute", from_unixtime(unix_timestamp(col("Date"), "yyyy-MM-dd HH:mm:ss"), "HH:mm")).show()//+-------------------+-----------+//| Date|hour:minute|//+-------------------+-----------+//|1970-01-01 06:00:00| 06:00|//+-------------------+-----------+
英文:
unix_timestamp converts timestamp to epoch/unix time.
- Use either
date_format,from_unixtime(unix_timestamp())functions to extracthour:minute.
Example:
df.withColumn("hour:minute",date_format(col("Date"),"HH:mm")).show()df.withColumn("hour:minute",from_unixtime(unix_timestamp(col("Date"),"yyyy-MM-dd HH:mm:ss"),"HH:mm")).show()//+-------------------+-----------+//| Date|hour:minute|//+-------------------+-----------+//|1970-01-01 06:00:00| 06:00|//+-------------------+-----------+
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