How to get just the field names from the given string in object format ( not using POJO ) from the following string using regex

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英文:

How to get just the field names from the given string in object format ( not using POJO ) from the following string using regex

问题

以下是字段的名称翻译：

  1. "{
  2.     account_number={
  3.     type=long
  4.     },
  5.     firstname={
  6.     type=text, fields={
  7.     keyword={
  8.     ignore_above=256, type=keyword
  9.             }
  10.         }
  11.     },
  12.     accountnumber={
  13.     type=long
  14.     },
  15.     address={
  16.     type=text, fields={
  17.     keyword={
  18.     ignore_above=256, type=keyword
  19.             }
  20.         }
  21.     },
  22.     gender={
  23.     type=text, fields={
  24.     keyword={
  25.     ignore_above=256, type=keyword
  26.             }
  27.         }
  28.     }
  29. }"

需要获取的字段名称是：account_number, firstname, accountnumber, address, gender。由于对象内部的内容不固定，因此无法使用POJO类。正则表达式可能会起作用。有什么建议吗？

英文:

String is as follows :

  1. "{
  2.     account_number={
  3.     type=long
  4.     },
  5.     firstname={
  6.     type=text, fields={
  7.     keyword={
  8.     ignore_above=256, type=keyword
  9.             }
  10.         }
  11.     },
  12.     accountnumber={
  13.     type=long
  14.     },
  15.     address={
  16.     type=text, fields={
  17.     keyword={
  18.     ignore_above=256, type=keyword
  19.             }
  20.         }
  21.     },
  22.     gender={
  23.     type=text, fields={
  24.     keyword={
  25.     ignore_above=256, type=keyword
  26.             }
  27.         }
  28.     }
  29. }"

I need to get only the names of these fields, i.e, account_number,firstname,accountnumber,address,gender. Pojo class won't work here since the content inside objects is not fixed. A reg ex may work. Any suggestions ?

答案1

得分: 1

  1. import java.util.HashSet;
  2. import java.util.Set;
  3. import java.util.regex.Matcher;
  4. import java.util.regex.Pattern;
  6. import org.json.JSONObject;
  8. public class SOTest {
  10.     public static void main(String args[]) {
  11.         Set<String> keywords = new HashSet<String>();
  12.         final String regex = "[a-z]\\w*";
  13.         String string = "{
  14.             account_number={
  15.             type=long
  16.             },
  17.             firstname={
  18.             type=text, fields={
  19.             keyword={
  20.             ignore_above=256, type=keyword
  21.             }
  22.             }
  23.             },
  24.             accountnumber={
  25.             type=long
  26.             },
  27.             address={
  28.             type=text, fields={
  29.             keyword={
  30.             ignore_above=256, type=keyword
  31.             }
  32.             }
  33.             },
  34.             gender={
  35.             type=text, fields={
  36.             keyword={
  37.             ignore_above=256, type=keyword
  38.             }
  39.             }
  40.             }
  41.         }";
  42.         final Pattern pattern = Pattern.compile(regex, Pattern.MULTILINE);
  43.         final Matcher matcher = pattern.matcher(string);
  44.         while(matcher.find()) {
  45.             String gp = matcher.group();
  46.             keywords.add(gp);
  47.         }
  48.         for (String keyword : keywords) {
  49.             string = string.replace(keyword, "\"" + keyword + "\"");
  50.         }
  51.         string = string.replace("=", ":");
  52.         System.out.println(string);
  53.         JSONObject jsonObject = new JSONObject(string);
  54.         System.out.println(jsonObject.keySet());
  55.     }
  56. }
英文:

Here I have converted ur string into JSON and then retrieved all the keys

  1. import java.util.HashSet;
  2. import java.util.Set;
  3. import java.util.regex.Matcher;
  4. import java.util.regex.Pattern;
  5. import org.json.JSONObject;
  6. public class SOTest {
  7. public static void main(String args[]) {
  8. Set&lt;String&gt; keywords = new HashSet&lt;String&gt;();
  9. final String regex = &quot;[a-z]\\w*&quot;;
  10. String string = &quot;{\n&quot;
  11. + &quot;    account_number={\n&quot;
  12. + &quot;    type=long\n&quot;
  13. + &quot;    },\n&quot;
  14. + &quot;    firstname={\n&quot;
  15. + &quot;    type=text, fields={\n&quot;
  16. + &quot;    keyword={\n&quot;
  17. + &quot;    ignore_above=256, type=keyword\n&quot;
  18. + &quot;            }\n&quot;
  19. + &quot;        }\n&quot;
  20. + &quot;    },\n&quot;
  21. + &quot;    accountnumber={\n&quot;
  22. + &quot;    type=long\n&quot;
  23. + &quot;    },\n&quot;
  24. + &quot;    address={\n&quot;
  25. + &quot;    type=text, fields={\n&quot;
  26. + &quot;    keyword={\n&quot;
  27. + &quot;    ignore_above=256, type=keyword\n&quot;
  28. + &quot;            }\n&quot;
  29. + &quot;        }\n&quot;
  30. + &quot;    },\n&quot;
  31. + &quot;    gender={\n&quot;
  32. + &quot;    type=text, fields={\n&quot;
  33. + &quot;    keyword={\n&quot;
  34. + &quot;    ignore_above=256, type=keyword\n&quot;
  35. + &quot;            }\n&quot;
  36. + &quot;        }\n&quot;
  37. + &quot;    }\n&quot;
  38. + &quot;}&quot;;
  39. final Pattern pattern = Pattern.compile(regex, Pattern.MULTILINE);
  40. final Matcher matcher = pattern.matcher(string);
  41. while(matcher.find()) {
  42. String gp = matcher.group();
  43. keywords.add(gp);
  44. }
  45. for (String keyword : keywords) {
  46. string = string.replace(keyword, &quot;\&quot;&quot;+keyword+&quot;\&quot;&quot;);
  47. }
  48. string = string.replace(&quot;=&quot;, &quot;:&quot;);
  49. System.out.println(string);
  50. JSONObject jsonObject = new JSONObject(string);
  51. System.out.println(jsonObject.keySet());
  52. }
  53. }

output

  1. [account_number, firstname, accountnumber, address, gender]

huangapple
  • 本文由 发表于 2020年5月5日 00:24:29
  • 转载请务必保留本文链接：https://go.coder-hub.com/61596927.html
  • java
  • regex
  • regex-group
  • string
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