英文:
How to delete from a particular string to end to the end of the paragraph in groovy
问题
我有这一段话，开头是请随意回复此电子邮件...，我想将从这一点开始直到段落末尾的内容替换为空字符串。我已经看了以下内容，但似乎并不起作用：
replaceAll
String s = replaceAll("Feel free to reply to this email..", " ") //这并没有帮助，因为我需要知道要替换的完整文本。
您的建议将不胜感激。
英文:
I have this paragraph that starts with Feel free to reply to this email..., I want to replace everything from this point that is from Feel free to reply to this email.. to the end to the end of the paragraph with an empty string. I have taken a look at the following but it seems not to work:
replaceAll
String s = replaceAll("Feel free to reply to this email..", " ") //this was not helpful since I need to know the complete text that I want to replace.
Your suggestions will be highly appreciated.
答案1
得分: 1
你可以在 replaceFirst 中使用以下正则表达式：
(?s)随意回复此电子邮件.*
请参阅Groovy演示。
(?s)随意回复此电子邮件.*模式首先匹配随意回复此电子邮件，然后.*匹配由于嵌入了(?s)标志选项而使。与默认情况下不匹配的任何字符，包括换行字符。
英文:
You may use the following regex with replaceFirst:
(?s)Feel free to reply to this email.*
See the Groovy demo
The (?s)Feel free to reply to this email.* pattern matches Feel free to reply to this email first and then .* matches all the rest of the text due to (?s) embedded flag option that makes . match any char including line break chars that . does not match by default.
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