英文:
loop through sections of an array
问题
我正在寻求一些关于一个问题的帮助。我目前正在尝试循环遍历一个二维数组的各个部分，但不确定如何做。
基本上，我会有一个4x4或9x9或25x25的数组，我需要能够迭代遍历块并检查重复项。
例如，对于4x4，我会遍历4个2x2的数组。
对于9x9，会有9个3x3的数组，依此类推。
我已经尝试了一段时间，但没有成功。
任何帮助都将是很好的，
谢谢
英文:
Was looking to see if i can get a bit of help with a problem. So i am currently trying to loop through sections of a 2d array and unsure how to do it.
essentially I’m going to have an array 4x4 or 9x9 or 25x25, and i need to be able to iterate over blocks and check for duplicates.
for example 4x4, i would iterate over 4 2x2 arrays.
the 9x9 would be 9 3x3 arrays etc.
been trying for a while but have had no luck
i have tried this
any help would be great,
cheers
答案1
得分: 1
如果数组始终是二维的，你可以这样做：
import java.util.ArrayList;
import java.util.List;
class Main {
public static void main(String[] args) {
// 初始化二维数组
int size = 3;
int[][] table = new int[size][size];
for (int row = 0; row < size; row++)
for (int col = 0; col < size; col++)
table[row][col] = (int) (20.0 * Math.random());
// 检查重复项
List<Integer> seen = new ArrayList<>();
List<Integer> duplicates = new ArrayList<>();
for (int row = 0; row < size; row++) {
for (int col = 0; col < size; col++) {
boolean exists = seen.contains(table[row][col]);
if (!exists) {
seen.add(table[row][col]);
continue;
}
duplicates.add(table[row][col]);
}
}
System.out.println(seen);
System.out.println(duplicates);
}
}
注意：我已经将代码中的一些符号进行了修正，使其更加符合Java编程语言的语法要求。
英文:
If the arrays are always 2d then you could do something like this:
import java.util.ArrayList;
import java.util.List;
class Main {
public static void main(String[] args) {
// Initialize the 2d array
int size = 3;
int[][] table = new int[size][size];
for (int row = 0; row < size; row ++)
for (int col = 0; col < size; col++)
table[row][col] = (int) (20.0 * Math.random());
// Scan for duplicates
List seen = new ArrayList();
List duplicates = new ArrayList();
for (int row = 0; row < size; row ++) {
for (int col = 0; col < size; col++) {
boolean exists = seen.contains(table[row][col]);
if (!exists) {
seen.add(table[row][col]);
continue;
}
duplicates.add(table[row][col]);
}
}
System.out.println(seen);
System.out.println (duplicates);
}
}
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