Hangman game: How to find the word?

I have to create a hangman game. I am stuck in the last step. In fact, when the user finds the word my input asks yet a letter.

Here an example: (the word to find is "non")

Enter your letter please : n

n _ n 

Enter your letter please : o

n o n 

Enter your letter please :

n o n

My problem is probably my wordFind, I don't understand how to manipulate this ?

        String[] words = {"yess", "non"};
String wordRandom = words[(int) (Math.random() *  words.length)];
boolean[] letterGuess = new boolean [wordRandom.length()];
boolean wordFind = false;
int numberAttempt = 5;
while(numberAttempt > 0 && !wordFind){
System.out.println("Number of attempt(s) " + numberAttempt);
for(int i=0; i < wordRandom.length(); i++){
if(letterGuess[i]){
System.out.print(wordRandom.charAt(i));
}
else{
System.out.print("- ");
}
}
System.out.println(" ");
System.out.print("Enter your letter please : ");
char letter = input.next().charAt(0);
int letterFound = 0;
boolean alreadyFound = false;
for(int i=0; i < wordRandom.length(); i++){
if(wordRandom.charAt(i) == letter){
if(letterGuess[i]){
alreadyFound  = true;
}
letterGuess[i] = true;
letterFound++;
}
}
if(alreadyFound){
System.out.println("Letter already proposed and it has been found ! ");
} else{
if(letterFound == 1){
System.out.println("The letter is correct ! ");
}
else if(letterFound  > 0){
System.out.println("The letter is " + letterFound  + " times in the word ! ");
}
else{
numberAttempt--;
System.out.println("The letter is not in the word ! ");
}
}
}

You need to add a solved condition like this

    boolean wordFind = false;
int numberAttempt = 5;
boolean solved = false;
while(numberAttempt > 0 && !wordFind && !solved){

after you update letterFound, set solved

letterFound++;
if (letterfound == wordRandom.length()) {
solved = true
}

Then at the end after the while loop, if solved is true, congratulate the user.

You can create a variable int amountCorrect = 0; and use that as a check. Every time the user gets a right letter, add to amountCorrect the number of letters there are. At the beginning of the while loop, create a boolean check that checks if the amountCorrect variable is the same as the length of the wordRandom. I know your code is kind of long, so I put a comment next to the lines where I added code:

    String[] words = { "yess", "non" };
String wordRandom = words[(int) (Math.random() * words.length)];
boolean[] letterGuess = new boolean[wordRandom.length()];
boolean wordFind = false;
int numberAttempt = 5;
int amountCorrect = 0; // The amountCorrect variable
while (numberAttempt > 0 && !wordFind) {
System.out.println("Number of attempt(s) " + numberAttempt);
// This is the boolean check
if (amountCorrect == wordRandom.length()) {
System.out.println("You Win!");
break;
}
for (int i = 0; i < wordRandom.length(); i++) {
if (letterGuess[i]) {
System.out.print(wordRandom.charAt(i));
} else {
System.out.print("- ");
}
}
System.out.println(" ");
System.out.print("Enter your letter please : ");
char letter = input.next().charAt(0);
int letterFound = 0;
boolean alreadyFound = false;
for (int i = 0; i < wordRandom.length(); i++) {
if (wordRandom.charAt(i) == letter) {
if (letterGuess[i]) {
alreadyFound = true;
}
letterGuess[i] = true;
letterFound++;
// add to amountCorrect
amountCorrect++;
}
}
if (alreadyFound) {
System.out.println("Letter already proposed and it has been found ! ");
} else {
if (letterFound == 1) {
System.out.println("The letter is correct ! ");
}
else if (letterFound > 0) {
System.out.println("The letter is " + letterFound + " times in the word ! ");
}
else {
numberAttempt--;
System.out.println("The letter is not in the word ! ");
}
}
}