英文:
How to get classpath resources by extension?
问题
假设我在类路径中有一些资源文件：
/a/b/c/x1.txt
/a/b/d/x2.txt
/a/b/e/x3.txt
我的代码并不知道这些资源文件的完整路径，它只知道它们的扩展名 .txt。
您会如何编写一个函数来返回具有扩展名 .txt 的资源文件的路径？
英文:
Suppose I've got a few resource files in my classpath:
/a/b/c/x1.txt
/a/b/d/x2.txt
/a/b/e/x3.txt
My code does not know the full paths of these resource files. It knows only their extension .txt.
How would you write a function to return the paths of the resources with extension .txt ?
答案1
得分: 2
尝试这样做：
Path path = Paths.get(YourClass.class.getResource("/resources").toURI());
List<String> result = Files.find(path, 100,
(p, a) -> p.toString().toLowerCase().endsWith(".txt"))
.map(Path::toString)
.collect(Collectors.toList());
英文:
Try this:
Path path = Paths.get(YourClass.class.getResource("/resources").toURI());
List<String> result = Files.find(path, 100,
(p, a) -> p.toString().toLowerCase().endsWith(".txt"))
.map(Path::toString)
.collect(Collectors.toList());
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