“Canvas: trying to draw too large bitmap” 在 Android Studio 中的问题。

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英文:

"Canvas: trying to draw too large bitmap" problem in Android Studio

问题

从网站获取bitmap时,出现了“Canvas: trying to draw too large”问题。

因此,我在谷歌上搜索了这个问题,许多人写了他们的解决方案,但这些解决方案是关于目录drawable中的位图文件的。

  • 如果从网站获取的位图图像太大怎么办?

这是我的代码。

            Thread mThread = new Thread() {
                @Override
                public void run() {
                    try {
                        URL url = new URL(postImgUrl);

                        HttpURLConnection conn = (HttpURLConnection) url.openConnection();
                        conn.setDoInput(true);
                        conn.connect();

                        InputStream inputStream = conn.getInputStream();
                        postImgBitmap = BitmapFactory.decodeStream(inputStream);
                        inputStream.close();
                        conn.disconnect();

                    } catch (MalformedURLException e) {
                        e.printStackTrace();
                    } catch (IOException e) {
                        e.printStackTrace();
                    }
                }
            };
            mThread.start();
            mThread.join();

            if (postImgBitmap != null){
                postImg.setImageBitmap(postImgBitmap);

当问题出现时,变量postImgUrl为"http://www.hstree.org/data/ck_tmp/202001/de3kOOtFqV6Bc2o7xCa7vg1UwFWJ.jpg",变量postImgImageView

请给我建议。

英文:

When I try to get bitmap from website, Canvas: trying to draw too large problem is occured.

So I search this problem on google and many people wrote their solutions, but that solution is about bitmap file in directory drawable.

  • What should I do if the bitmap image taken from the website is too large?

This is my code.

            Thread mThread = new Thread() {
                @Override
                public void run() {
                    try {
                        URL url = new URL(postImgUrl);

                        HttpURLConnection conn = (HttpURLConnection) url.openConnection();
                        conn.setDoInput(true);
                        conn.connect();

                        InputStream inputStream = conn.getInputStream();
                        postImgBitmap = BitmapFactory.decodeStream(inputStream);
                        inputStream.close();
                        conn.disconnect();

                    } catch (MalformedURLException e) {
                        e.printStackTrace();
                    } catch (IOException e) {
                        e.printStackTrace();
                    }
                }
            };
            mThread.start();
            mThread.join();

            if (postImgBitmap != null){
                postImg.setImageBitmap(postImgBitmap);

When a problem occurs, variable postImgUrl is "http://www.hstree.org/data/ck_tmp/202001/de3kOOtFqV6Bc2o7xCa7vg1UwFWJ.jpg" and variable postImg is ImageView.

Please advise me.

答案1

得分: 0

以下是翻译好的内容:

错误意味着位图的大小对于ImageView来说太大了。
在将位图设置到ImageView之前,您可以使用Bitmap.createScaledBitmap()将大的位图缩放为较小的位图。然后,您可以安全地将位图设置到ImageView上。

示例代码:

public class MainActivity extends AppCompatActivity {
    private static final String imageUrl
        = "http://www.hstree.org/data/ck_tmp/202001/de3kOOtFqV6Bc2o7xCa7vg1UwFWJ.jpg";

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);
        final ImageView imageView = findViewById(R.id.imageView);

        new Thread(new Runnable() {
            @Override
            public void run() {
                URL url = null;
                try {
                    url = new URL(imageUrl);
                } catch (MalformedURLException e) {
                    e.printStackTrace();
                }

                try (BufferedInputStream bufferedInputStream
                        = new BufferedInputStream(url.openStream())) {
                    Bitmap bitmap = BitmapFactory.decodeStream(bufferedInputStream);

                    final Bitmap scaledBitmap = Bitmap.createScaledBitmap(
                        bitmap,
                        (int) (bitmap.getWidth() * 0.1),
                        (int) (bitmap.getHeight() * 0.1),
                        true
                    );

                    runOnUiThread(new Runnable() {
                        @Override
                        public void run() {
                            imageView.setImageBitmap(scaledBitmap);
                        }
                    });
                } catch (IOException e) {
                    e.printStackTrace();
                }
            }
        }).start();
    }
}

注意:我已经去掉了HTML编码中的",以便代码在Java中正确显示。

英文:

The error means the size of Bitmap is too large for the ImageView.
Before setImageBitmap() to ImageView, you can scale the large Bitmap to a smaller one with Bitmap.createScaledBitmap(). Then you can safely set the Bitmap to ImageView.

A sample code:

public class MainActivity extends AppCompatActivity {
private static final String imageUrl
= "http://www.hstree.org/data/ck_tmp/202001/de3kOOtFqV6Bc2o7xCa7vg1UwFWJ.jpg";
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
final ImageView imageView = findViewById(R.id.imageView);
new Thread(new Runnable() {
@Override
public void run() {
URL url = null;
try {
url = new URL(imageUrl);
} catch (MalformedURLException e) {
e.printStackTrace();
}
try (BufferedInputStream bufferedInputStream
= new BufferedInputStream(url.openStream())) {
Bitmap bitmap = BitmapFactory.decodeStream(bufferedInputStream);
final Bitmap scaledBitmap = Bitmap.createScaledBitmap(
bitmap,
(int) (bitmap.getWidth() * 0.1),
(int) (bitmap.getHeight() * 0.1),
true
);
runOnUiThread(new Runnable() {
@Override
public void run() {
imageView.setImageBitmap(scaledBitmap);
}
});
} catch (IOException e) {
e.printStackTrace();
}
}
}).start();
}
}

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  • 本文由 发表于 2020年4月10日 12:53:23
  • 转载请务必保留本文链接:https://go.coder-hub.com/61134238.html
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