“Canvas: trying to draw too large bitmap” 在 Android Studio 中的问题。

huangapple
go评论154阅读模式
英文:

"Canvas: trying to draw too large bitmap" problem in Android Studio

问题

从网站获取bitmap时，出现了“Canvas: trying to draw too large”问题。

因此，我在谷歌上搜索了这个问题，许多人写了他们的解决方案，但这些解决方案是关于目录drawable中的位图文件的。

  • 如果从网站获取的位图图像太大怎么办？

这是我的代码。

  1.             Thread mThread = new Thread() {
  2.                 @Override
  3.                 public void run() {
  4.                     try {
  5.                         URL url = new URL(postImgUrl);
  7.                         HttpURLConnection conn = (HttpURLConnection) url.openConnection();
  8.                         conn.setDoInput(true);
  9.                         conn.connect();
  11.                         InputStream inputStream = conn.getInputStream();
  12.                         postImgBitmap = BitmapFactory.decodeStream(inputStream);
  13.                         inputStream.close();
  14.                         conn.disconnect();
  16.                     } catch (MalformedURLException e) {
  17.                         e.printStackTrace();
  18.                     } catch (IOException e) {
  19.                         e.printStackTrace();
  20.                     }
  21.                 }
  22.             };
  23.             mThread.start();
  24.             mThread.join();
  26.             if (postImgBitmap != null){
  27.                 postImg.setImageBitmap(postImgBitmap);

当问题出现时，变量postImgUrl为"http://www.hstree.org/data/ck_tmp/202001/de3kOOtFqV6Bc2o7xCa7vg1UwFWJ.jpg"，变量postImg是ImageView。

请给我建议。

英文:

When I try to get bitmap from website, Canvas: trying to draw too large problem is occured.

So I search this problem on google and many people wrote their solutions, but that solution is about bitmap file in directory drawable.

  • What should I do if the bitmap image taken from the website is too large?

This is my code.

  1.             Thread mThread = new Thread() {
  2.                 @Override
  3.                 public void run() {
  4.                     try {
  5.                         URL url = new URL(postImgUrl);
  7.                         HttpURLConnection conn = (HttpURLConnection) url.openConnection();
  8.                         conn.setDoInput(true);
  9.                         conn.connect();
  11.                         InputStream inputStream = conn.getInputStream();
  12.                         postImgBitmap = BitmapFactory.decodeStream(inputStream);
  13.                         inputStream.close();
  14.                         conn.disconnect();
  16.                     } catch (MalformedURLException e) {
  17.                         e.printStackTrace();
  18.                     } catch (IOException e) {
  19.                         e.printStackTrace();
  20.                     }
  21.                 }
  22.             };
  23.             mThread.start();
  24.             mThread.join();
  26.             if (postImgBitmap != null){
  27.                 postImg.setImageBitmap(postImgBitmap);

When a problem occurs, variable postImgUrl is "http://www.hstree.org/data/ck_tmp/202001/de3kOOtFqV6Bc2o7xCa7vg1UwFWJ.jpg" and variable postImg is ImageView.

Please advise me.

答案1

得分: 0

以下是翻译好的内容：

错误意味着位图的大小对于ImageView来说太大了。
在将位图设置到ImageView之前，您可以使用Bitmap.createScaledBitmap()将大的位图缩放为较小的位图。然后，您可以安全地将位图设置到ImageView上。

示例代码：

  1. public class MainActivity extends AppCompatActivity {
  2.     private static final String imageUrl
  3.         = "http://www.hstree.org/data/ck_tmp/202001/de3kOOtFqV6Bc2o7xCa7vg1UwFWJ.jpg";
  5.     @Override
  6.     protected void onCreate(Bundle savedInstanceState) {
  7.         super.onCreate(savedInstanceState);
  8.         setContentView(R.layout.activity_main);
  9.         final ImageView imageView = findViewById(R.id.imageView);
  11.         new Thread(new Runnable() {
  12.             @Override
  13.             public void run() {
  14.                 URL url = null;
  15.                 try {
  16.                     url = new URL(imageUrl);
  17.                 } catch (MalformedURLException e) {
  18.                     e.printStackTrace();
  19.                 }
  21.                 try (BufferedInputStream bufferedInputStream
  22.                         = new BufferedInputStream(url.openStream())) {
  23.                     Bitmap bitmap = BitmapFactory.decodeStream(bufferedInputStream);
  25.                     final Bitmap scaledBitmap = Bitmap.createScaledBitmap(
  26.                         bitmap,
  27.                         (int) (bitmap.getWidth() * 0.1),
  28.                         (int) (bitmap.getHeight() * 0.1),
  29.                         true
  30.                     );
  32.                     runOnUiThread(new Runnable() {
  33.                         @Override
  34.                         public void run() {
  35.                             imageView.setImageBitmap(scaledBitmap);
  36.                         }
  37.                     });
  38.                 } catch (IOException e) {
  39.                     e.printStackTrace();
  40.                 }
  41.             }
  42.         }).start();
  43.     }
  44. }

注意：我已经去掉了HTML编码中的"，以便代码在Java中正确显示。

英文:

The error means the size of Bitmap is too large for the ImageView.
Before setImageBitmap() to ImageView, you can scale the large Bitmap to a smaller one with Bitmap.createScaledBitmap(). Then you can safely set the Bitmap to ImageView.

A sample code:

  1. public class MainActivity extends AppCompatActivity {
  2. private static final String imageUrl
  3. = "http://www.hstree.org/data/ck_tmp/202001/de3kOOtFqV6Bc2o7xCa7vg1UwFWJ.jpg";
  4. @Override
  5. protected void onCreate(Bundle savedInstanceState) {
  6. super.onCreate(savedInstanceState);
  7. setContentView(R.layout.activity_main);
  8. final ImageView imageView = findViewById(R.id.imageView);
  9. new Thread(new Runnable() {
  10. @Override
  11. public void run() {
  12. URL url = null;
  13. try {
  14. url = new URL(imageUrl);
  15. } catch (MalformedURLException e) {
  16. e.printStackTrace();
  17. }
  18. try (BufferedInputStream bufferedInputStream
  19. = new BufferedInputStream(url.openStream())) {
  20. Bitmap bitmap = BitmapFactory.decodeStream(bufferedInputStream);
  21. final Bitmap scaledBitmap = Bitmap.createScaledBitmap(
  22. bitmap,
  23. (int) (bitmap.getWidth() * 0.1),
  24. (int) (bitmap.getHeight() * 0.1),
  25. true
  26. );
  27. runOnUiThread(new Runnable() {
  28. @Override
  29. public void run() {
  30. imageView.setImageBitmap(scaledBitmap);
  31. }
  32. });
  33. } catch (IOException e) {
  34. e.printStackTrace();
  35. }
  36. }
  37. }).start();
  38. }
  39. }

huangapple
  • 本文由 发表于 2020年4月10日 12:53:23
  • 转载请务必保留本文链接：https://go.coder-hub.com/61134238.html
  • android
  • android-bitmap
  • java
匿名

发表评论

匿名网友

:?: :razz: :sad: :evil: :!: :smile: :oops: :grin: :eek: :shock: :???: :cool: :lol: :mad: :twisted: :roll: :wink: :idea: :arrow: :neutral: :cry: :mrgreen:

确定