英文:
How can I write an if block using lambda?
问题
String str = "Hello";String x = "1";if (Stream.of("Hello", "Helloo", "Hellooo", "Hellooo...").anyMatch(s -> s.equals(str))) {if (x != null) {// do something} else {// do something else}}
英文:
Could you please tell me how can I write this expression using lambda/ Java 8 ?
String str = "Hello";String x = "1";if(str.equals("Hello") || str.equals("Helloo") ||str.equals("Hellooo") || str.equals("Hellooo...")) {if(x != null) {// do something} else {// do something else}}
答案1
得分: 4
你可以使用一个Set来存储所有的问候语，然后使用filter和ifPresent来制定条件：
Stream.of("Hello", "Helloo", "Hellooo", "Hellooo...").filter(str::equals).findAny().ifPresent(c -> {if (x != null) {// 做某事} else {// 做其他事情}});
但在你的情况下，我建议使用以下方式：
if (str.matches("Hell[o]{1,4}(\\.{4})?")) {if (x != null) {// 做某事} else {// 做其他事情}}
关于正则表达式，你可以根据你的输入进行改进，我只是快速制作了一个示例来展示另一种解决方案。
英文:
You can use a Set to store all your salutations, and then use filter and ifPresent to make your condition:
Stream.of("Hello", "Helloo", "Hellooo", "Hellooo...").filter(str::equals).findAny().ifPresent(c -> {if (x != null) {// do something} else {// do something else}});
But in your case, I would like to use:
if (str.matches("Hell[o]{1,4}(\\.{4})?")) {if (x != null) {// do something} else {// do something else}}
About the regex, you can improve it based on your inputs, I made a quick one to show you the other solution.
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