Is there a way in which multiple threads can print the current time(Time in milli seconds) exactly same?

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英文:

Is there a way in which multiple threads can print the current time(Time in milli seconds) exactly same?

问题

使用Executor Service,我需要运行10个线程。而且每个线程都应该打印出当前的毫秒时间,并且我需要确保所有这些线程始终打印出完全相同的时间。
我已经尝试使用CyclicBarrier,但它不起作用。
这样做有可能吗?

英文:

Using Executor Service's I need to run 10 threads. And each of these threads should print the current time in milliseconds and I need to ensure that all these threads always print the exact same time.
I have tried using CyclicBarrier but it does not work.

Is it possible to do so?

答案1

得分: 2

你可以使用CountDownLatch来实现你所尝试的功能;

import java.util.concurrent.CountDownLatch;
import java.util.concurrent.ExecutorService;
import java.util.concurrent.Executors;

public class TestApp {
    private static final int THREAD_COUNT = 10;

    public static void main(String... args) throws Exception {
        ExecutorService executorService = Executors.newFixedThreadPool(THREAD_COUNT);
        final CountDownLatch countDownLatch = new CountDownLatch(THREAD_COUNT);
        for(int i=0; i<THREAD_COUNT; i++) {
            executorService.execute(() -> {
                countDownLatch.countDown();
                try {
                    countDownLatch.await();
                    System.out.println(Thread.currentThread().getName() + " - " + System.currentTimeMillis());
                } catch (InterruptedException e) {
                    // TODO Auto-generated catch block
                    e.printStackTrace();
                }
            });
        }
    }
}

结果

>     pool-1-thread-5 - 1586432194060
>     pool-1-thread-8 - 1586432194060
>     pool-1-thread-4 - 1586432194060
>     pool-1-thread-6 - 1586432194060
>     pool-1-thread-1 - 1586432194060
>     pool-1-thread-2 - 1586432194060
>     pool-1-thread-9 - 1586432194060
>     pool-1-thread-3 - 1586432194060
>     pool-1-thread-7 - 1586432194060
>     pool-1-thread-10 - 1586432194060
英文:

You can make use of a CountDownLatch to achieve what you are trying;

import java.util.concurrent.CountDownLatch;
import java.util.concurrent.ExecutorService;
import java.util.concurrent.Executors;

public class TestApp {
	private static final int THREAD_COUNT = 10;
	
	public static void main(String... args) throws Exception {
		ExecutorService executorService = Executors.newFixedThreadPool(THREAD_COUNT);
		final CountDownLatch countDownLatch = new CountDownLatch(THREAD_COUNT);
		for(int i=0;i&lt;THREAD_COUNT;i++) {
			executorService.execute(() -&gt; {
				countDownLatch.countDown();
				try {
					countDownLatch.await();
					System.out.println(Thread.currentThread().getName() + &quot; - &quot; + System.currentTimeMillis());
				} catch (InterruptedException e) {
					// TODO Auto-generated catch block
					e.printStackTrace();
				}
			});
		}
		
	}
}

Result

> pool-1-thread-5 - 1586432194060
> pool-1-thread-8 - 1586432194060
> pool-1-thread-4 - 1586432194060
> pool-1-thread-6 - 1586432194060
> pool-1-thread-1 - 1586432194060
> pool-1-thread-2 - 1586432194060
> pool-1-thread-9 - 1586432194060
> pool-1-thread-3 - 1586432194060
> pool-1-thread-7 - 1586432194060
> pool-1-thread-10 - 1586432194060

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  • 本文由 发表于 2020年4月9日 19:24:19
  • 转载请务必保留本文链接:https://go.coder-hub.com/61120041.html
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