英文:
Repeating element in array x amount of times in same order
问题
以下是翻译好的部分：
问题要求：「编写一个方法，接受两个参数：一个 String[] 数组和一个表示重复次数的 int numRepeats。返回一个新数组，其中每个元素都重复 numRepeats 次。」
例如：
repeatElements(new String[]{"hello", "world"}, 3)
应返回一个包含以下元素的新数组：
["hello", "hello", "hello", "world", "world", "world"]
我目前的代码是：
public String[] repeatElements(String[] array, int numRepeats)
{
String[] arr = new String[array.length * numRepeats];
if(numRepeats == 0)
return arr;
if(array.length == 0)
return arr;
int m = 0;
for(int i = 0; i < numRepeats; i++)
{
arr[m++] = array[0];
}
return arr;
}
我的解决方案只适用于某些测试，而不是所有测试。如何修复我的代码，以便它可以解决所有给定的测试？
英文:
The question asks: "Write a method that takes 2 parameters: a String[] array, and an int numRepeats representing the number of times to repeat each element in the array. Return a new array with each element repeated numRepeats times."
For example:
repeatElements(new String[]{"hello", "world"}, 3)
Should return a new array with the elements:
["hello", "hello", "hello", "world", "world", "world"]
The code I have so far is:
public String[] repeatElements(String[] array, int numRepeats)
{
String[] arr = new String[array.length * numRepeats];
if(numRepeats == 0)
return arr;
if(array.length == 0)
return arr;
int m = 0;
for(int i = 0; i < numRepeats; i++)
{
arr[m++] = array[0];
}
return arr;
}
My solution only works for some tests, not all of them. How do I fix my code so it can solve all tests given?
答案1
得分: 0
你的循环只复制了数组的第一个元素。你本应该将所有元素复制 numRepeats 次。类似这样：
for (String s : array) {
for (int i = 0; i < numRepeats; i++) {
arr[m++] = s;
}
}
将其理解为对于数组中的每个 String s，将 s 赋值给 arr 中的位置 m（然后递增 m）。
英文:
Your loop only copies the first element of array. You were supposed to copy all of the elements numRepeats times. Something like,
for (String s : array) {
for (int i = 0; i < numRepeats; i++) {
arr[m++] = s;
}
}
Read that as for each String s in array assign s to position m in arr (and increment m afterward).
答案2
得分: 0
你需要另一个嵌套循环来重复array中的元素，重复次数为numRepeats。
按照以下方式进行操作：
import java.util.Arrays;
public class Main {
public static void main(String[] args) {
System.out.println(Arrays.toString(repeatElements(new String[] { "hello", "world" }, 3)));
}
static String[] repeatElements(String[] array, int numRepeats) {
String[] arr = new String[array.length * numRepeats];
if (numRepeats == 0)
return arr;
if (array.length == 0)
return arr;
int m = 0;
for (int i = 0; i < array.length; i++) {
for (int j = 1; j <= numRepeats; j++) {
arr[m++] = array[i];
}
}
return arr;
}
}
输出:
[hello, hello, hello, world, world, world]
嵌套循环也可以写成以下形式：
for (int j = 1; j <= numRepeats; j++) {
for (int i = 0; i < array.length; i++) {
arr[m++] = array[i];
}
}
英文:
You need another nested loop to repeat the elements of array for numRepeats number of times.
Do it as follows:
import java.util.Arrays;
public class Main {
public static void main(String[] args) {
System.out.println(Arrays.toString(repeatElements(new String[] { "hello", "world" }, 3)));
}
static String[] repeatElements(String[] array, int numRepeats) {
String[] arr = new String[array.length * numRepeats];
if (numRepeats == 0)
return arr;
if (array.length == 0)
return arr;
int m = 0;
for (int i = 0; i < array.length; i++) {
for (int j = 1; j <= numRepeats; j++) {
arr[m++] = array[i];
}
}
return arr;
}
}
Output:
[hello, hello, hello, world, world, world]
The nested loops can also be written as follows:
for (int j = 1; j <= numRepeats; j++) {
for (int i = 0; i < array.length; i++) {
arr[m++] = array[i];
}
}
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