哪个更高效?为映射的值临时结果声明一个对象?还是直接从映射根获取?

huangapple go评论86阅读模式
英文:

which one is more efficient? Declare an object for the temp result of a map's values? Or directly fetch from the map root?

问题

以下是翻译好的部分:

我之前使用过一段时间的Java。但是一直有一个以下的问题。假设我有一个名为 Result 的类。

public class Result {

     private List<Entity1> entity1List;
     private Map<String, Entity2> entity2Map;
     private Map<Integer, Entity3> entity3Map;

     // ......
}

现在我有一个方法要使用这个类内部的结果。哪种方式更有效呢?

方式 1:

public void test1(Result result, List<User> users) {
      Map<String, Entity2> entity2Map = result.getEntity2Map();
      for (User user : users) {
           System.out.println(entity2Map.get(user.getUID()));
      }
}

方式 2:

public void test1(Result result, List<User> users) {
      for (User user : users) {
          System.out.println(result.getEntity2Map().get(user.getUID()));
      }
}

哪种方式更有效?或者它们是相同的吗?谢谢。

英文:

I used java for a while. But always have a question as below. Let's say I have a Result class

public class Result {

     private List&lt;Entity1&gt; entity1List;
     private Map&lt;String, Entity2&gt; entity2Map;
     private Map&lt;Integer, Entity3&gt; entity3Map;

     ......
}

Now I have method to use the inside results of this class. Which way is more efficient?

Way 1:

public void test1 (Result result, List&lt;User&gt; users) {
      Map&lt;String, Entity2&gt; entity2Map = result.getEntity2Map();
      for (User user : users) {
           System.out.println(entity2Map.get(user.getUID()));
      }
} 

Way 2:

public void test1 (Result result, List&lt;User&gt; users) {
      for (User user : users) {
          System.out.println(result.getEntity2Map().get(user.getUID()));
      }
} 

Which way is more efficient? Or they are the same? Thanks.

答案1

得分: 1

这更像是关于编译器行为的问题,取决于方法.getEntity2Map()的具体实现。

如果该方法只是返回一个引用而没有执行其他操作,那么编译器可能会注意到这一点,并将Way 1优化为Way 2。您可以通过对class文件进行反编译来查看编译器的优化情况。这里是一个关于此的栈内问题。

一般来说,最好使用Way 1,因为您会显式地创建一个临时变量。如果方法.getEntity2Map()被反复调用,而编译器没有进行优化,那么每次调用都会创建一个新的堆栈帧。每次堆栈帧的创建都需要时间;如果方法的结果始终不会改变,那么这将是浪费的时间。

英文:

This is more of a question about what the compiler will do and depends on what the method .getEntity2Map() does.

If the method is just returning a reference without doing anything else, then the compiler may notice that and will make Way 1 out of Way 2. You can check whatever the compiler did by decompiling the class file. Here is a question on SO about the how.

In general, it's probably better to use Way 1 because you explicitly create a temporary variable. If the method .getEntity2Map() is called again and again and the compiler doesn't optimize that, a new stack frame is created for each call. Each creation of a stack frame takes time; if the result of the method doesn't change anyways, this is wasted time.

huangapple
  • 本文由 发表于 2020年4月7日 15:53:49
  • 转载请务必保留本文链接:https://go.coder-hub.com/61075265.html
匿名

发表评论

匿名网友

:?: :razz: :sad: :evil: :!: :smile: :oops: :grin: :eek: :shock: :???: :cool: :lol: :mad: :twisted: :roll: :wink: :idea: :arrow: :neutral: :cry: :mrgreen:

确定